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zysi [14]
2 years ago
13

A sample contains 110 g of a radioactive isotope. how much radioactive isotope will remain in the sample after 1 half-life?

Physics
1 answer:
Lerok [7]2 years ago
5 0

Answer:

The half-life of a radioactive isotope is the time such that the initial amount of the isotope is reduced to its half.

Thus, if we start with A grams of a given radioactive isotope, after a 1 half-life, we will have A/2 grams of the radioactive isotope.

In this case, we know that the sample has 110g of a radioactive isotope.

Then, after 1 half-life, we should have half of 110g, which is:

110g/2 = 55g

Then we should have 55 g of a radioactive isotope.

The answer that is closer to this result is option d (50 g), so that is the correct one.

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3 years ago
A certain corner of a room is selected as the origin of a rectangular coordinate system. If a fly is crawling on an adjacent wal
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2.59 m

Explanation:

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5 0
3 years ago
A projectile is fired at an upward angle of 45.0º from the top of a 265-m cliff with a speed of .sm 185 What will be its speed w
nignag [31]

The final velocity of the projectile when it strikes the ground below is 198.51 m/s.

<h3>Time of motion of the projectile</h3>

The time taken for the projectile to fall to the ground is calculated as follows;

h = vt + ¹/₂gt²

where;

  • h is height of the cliff
  • v is velocity
  • t is time of motion

265 = (185 x sin45)t + (0.5)(9.8)t²

265 = 130.8t + 4.9t²

4.9t² + 130.8t - 265 = 0

solve the quadratic equation using formula method,

t = 1.89 s

<h3>Final velocity of the projectile</h3>

vyf = vyi + gt

where;

  • vyf is the final vertical velocity
  • vyi is initial vertical velocity

vyf = (185 x sin45) + (9.8 x 1.89)

vyf = 149.322 m/s

vxf = vxi

where;

  • vxf is the final horizontal velocity
  • vxi is the initial horizontal velocity

vxf = 185 x cos(45)

vxf = 130.8 m/s

vf = √(vyf² + vxf²)

where;

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Learn more about final velocity here: brainly.com/question/6504879

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