1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Leviafan [203]
3 years ago
13

Explain the following statement: In a windowless proportional counter, the output pulse height from an alpha particle source wil

l increase with increasing alpha energy whereas for beta particles the opposite is true.
Engineering
1 answer:
-BARSIC- [3]3 years ago
5 0

Answer / Explanation:

Regarding α and β Particles in Windowless Counter, the range of α particles is lower than β particles. Alpha particles typically have range less than the dimensions of the gas chamber so that proportional  counters are able to easily record. Hence,  with almost 100% efficiency, each particle which enters the so called active volume.

Then, since the pulse height spectra depends on the number of ion pairs which have formed,  an aplha particle with higher energy creates more ion pairs in the chamber.  However, beta particle range usually exceeds the dimensions of the chamber and therefore  most of the betas hit the walls where they deposit energy. Then, fewer ion pairs are formed  because very few β’s give their energy to the bulk gas.

You might be interested in
Convert the following pairs of voltage and current waveforms to phasor form. Each pair of waveforms corresponds to an unknown el
exis [7]

Answer:

a) V = 20 ∠30⁰    ,    I = 4 ∠-210⁰    Z inductive    L = 0,0125 H

b) V = 9∠-60⁰      ,    I = 4 ∠ 190⁰    Z capacitive C = 4,94 *10⁻⁴ F

c) V = 13 ∠240⁰   ,    I = 7 ∠ 150⁰    Z Inductive  L = 0,0074 H

Explanation:

a) v(t) = 20 cos (400*t + 30 )

Phasor form    V = 20 ∠30⁰

i(t) = 4 sin (400*t - 120)

First we need to transform 4sin( 400t - 120 ) as  function cosine

we know that  sin ( x + 90 )  =  cos x

Then  sin ( 400*t -120 )  = cos ( 400*t  - 120 -90 )  = cos ( 400t - 120 - 90)

Phasor form  I = 4 ∠-210⁰

To have the impedance nature we compute

Z = V / I      ⇒  Z = 20 ∠30⁰ / 4  ∠-210⁰    Z = 5 ∠-180⁰

We notice that  voltage advances the current then we are in presence of an inductive impedance

5 = wl      ⇒  5  = 400 *L       ⇒  L  =    0,0125 H        

b) v(t) = 9 cos ( 900t - 60 )

V = 9∠-60⁰

i(t)  = 4 sin ( 900t + 280 )    ⇒  i(t) = 4 cos ( 900t + 280 - 90)

i(t) = 4 cos (900t + 190 )    ⇒  I = 4 ∠ 190⁰

Z = V/I    ⇒  Z = 9∠-60⁰ / 4  ∠ 190⁰    Z = 2,25 ∠-250

In this case the current advances the voltage. Impedance capacitive

1/wc  = 1/ 900*C       1/wc = Z   ⇒ 2,25 = 1/ 900*C

2,25*900 = 1/C     ⇒  2025 =1/C     ⇒  C = 4,94 *10⁻⁴ F

c) v(t) = - 13 cos ( 250t + 60 )

v(t) = 13 cos ( 250t + 60 +180 )    ⇒ v(t) = 13 cos ( 250t +240)

Phasor Form

V = 13 ∠240⁰

i(t) = 7 sin (250t + 240 - 90)  ⇒  i(t) = 7 sin (250t + 150)

Phasor Form  I = 7  ∠150⁰

Z = 13∠240⁰ / 7 ∠150⁰    ⇒  Z = 1,86 ∠ 90⁰

Voltage advances the current then the impedance is inductive

wl = 250L     250 L = 1,86     L  = 1,86/250     L = 0,0074 H

7 0
3 years ago
Can you gift points in this if yes please send some
dimaraw [331]
No, you can’t sorry :(
4 0
4 years ago
Read 2 more answers
Consider a very long, cylindrical fin. The temperature of the fin at the tip and base are 25 °C and 50 °C, respectively. The dia
Mrrafil [7]

Answer:

The fin temperature in °C at a distance of 10 cm from the base = 33.78°C

Explanation:

The following assumptions will be made to solve this problem

- The heat transfer coefficient does not change with the time or distance.

- The temperature of the fins varies just in only one direction.

The temperature of the fin at x = 10 cm = 0.10 m from the base can be calculated from the temperature variation with distance formula for a very long fin.

(T - T∞) = (T₀ - T∞)e⁻ᵐˣ

T = T(x) = temperature at any point along the fin

T∞ = temperature at the tip of the fin = ambient temperature = 25°C

T₀ = temperature at the base of thw fin = 50°C

x = any distance along the length of the fin from the base of the fin = 0.1 m

m = √(hP/KA)

h = Heat transfer coefficient = 123 W/m².K

P = perimeter in contact with the base = πD = π × 0.03 = 0.0943 m

K = thermal conductivity = 150 W/m.K

A = surface area in contact with the base = πD²/4 = π(0.03)²/4 = 0.0007071 m²

m = √(123 × 0.0943)/(150 × 0.0007071)

m = 10.46

mx = 10.46 × 0.1 = 1.046

(T - 25) = (50 - 25) e⁻¹•⁰⁴⁶

T = 25 + 25 e⁻¹•⁰⁴⁶ = 25 + 8.78 = 33.78°C

8 0
3 years ago
The function below takes a single parameter, a list of numbers called number_list. Complete the function to return a string of t
makkiz [27]

Answer:

The solution code is written in Python:

  1. def convertCSV(number_list):
  2.    str_list = []
  3.    for num in number_list:
  4.        str_list.append(str(num))
  5.    
  6.    return ",".join(str_list)
  7. result = convertCSV([22,33,44])
  8. print(result)

Explanation:

Firstly, create a function "convertCSV" with one parameter "number_list". (Line 1)

Next, create an empty list and assign it to a new variable <em>str_list</em>. (Line 2)

Use for-loop to iterate through all the number in the <em>number_list</em>.(Line 4). Within the loop, each number is converted to a string using the Python built-in function <em>str() </em>and then use the list append method to add the string version of the number to <em>str_list</em>.

Use Python string<em> join() </em>method to join all the elements in the str_list as a single string. The "," is used as a separator between the elements (Line 7) . At the end return the string as an output.

We can test the function by calling the function and passing [22,33,34] as an argument and we shall see "22,33,44" is printed as an output. (Line 9 - 10)

6 0
3 years ago
Estimate the quantity of soil to be excavated from the borrow pit​
Serggg [28]

Answer

1056

Explanation:

for example

A soil is to be excavated from a borrow pit which has a density of 1.75g/cc and water content of 12%. The G is 2.7 the soil is compacted to that water content of 18% and dry density of 1.65g/cc. for 1000 m3 of soil used in fill estimate

Quantity of soil to be excavated from pit in m3

6 0
3 years ago
Other questions:
  • Explain the two advantages and the two disadvantages of fission as an energy source.
    12·1 answer
  • How does an airfoil create lift?
    6·1 answer
  • What is the purpose of a presentation model? to fabricate a prototype to test the efficiency of the manufacturing process to tes
    15·1 answer
  • Automobile engines normally have
    8·1 answer
  • The relationship between the pressure drop per unit length along a smooth-walled, horizontal microfluidic channel and the variab
    6·1 answer
  • The preparation of a formal SEMP is usually a required portion of a contractor’s proposal for a competitive system development p
    8·1 answer
  • A. Briefly describe the microstructural difference between spheroidite and tempered martensite. Explain why tempered martensite
    14·1 answer
  • There are 22 people in the classroom 12 are we
    5·2 answers
  • How does science and technology address the problems of the society?
    6·2 answers
  • Although studs are sometimes spaced 24" O.C. in residential structures, a spacing of_____ O.C. is more commonly used.
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!