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andriy [413]
3 years ago
7

Suppose that you and two classmates are discussing the design of a roller coaster. One classmate says that each summit must be l

ower than the preceding one. Your other classmate says this is nonsense, for as long as the first one is the highest, it doesn’t matter what height the others are. What do you say
Engineering
1 answer:
Kitty [74]3 years ago
8 0

Answer:

The second classmate is right.

Explanation:

The height of first summit provides the potential energy it will use to climb the following ones.

Ep = m * g * h

Where

m: mass

g: acceleration of gravity

h: height

When the train goes downwards the potential energy is converted into kinetic energy (manifested as speed) and when it climbs it consumes its kinetical energy. As long as no summit is taller than the first the train should have enough energy to climb them.

Also it must be noted that friction also consumes energy, and if the track is too lomg all the energy might be consumed by it.

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An AX ceramic compound has the rock salt crystal structure. If the radii of the A and X ions are 0.137 and 0.241 nm, respectivel
Tju [1.3M]

Answer:

c) 1.75 g/cm³

Explanation:

Given that

Radii of the A ion, r(c) = 0.137 nm

Radii of the X ion, r(a) = 0.241 nm

Atomic weight of the A ion, A(c) = 22.7 g/mol

Atomic weight of the X ion, A(a) = 91.4 g/mol

Avogadro's number, N = 6.02*10^23 per mol

Solution is attached below

3 0
3 years ago
Calculate the force of attraction between a K+ and an O2- ion the centers of which are seperared by a distance of 1.5 nm.
Ymorist [56]

Answer:

F=2.04\times 10^{-10} N

Explanation:

Given that

q_1=1\times 1.6\times 10^{-19}

q_2=2\times 1.6\times 10^{-19}

r= 1.5 nm

We know that force between two charge given as follows

F=K\dfrac{q_1q_2}{r^2}

Where K is the constant

Noe by putting the values

q_1\times q_2=2\times 1.6\times1.6\times 10^{-38}

F=8.98\times 10^9 \times \dfrac{5.12\times 10^{-38}}{\left ( 1.5\times10^{-9} \right )^2}

F=2.04\times 10^{-10} N

8 0
3 years ago
6.3 In a particular technology, a small BJT operating at conducts a collector current of 100 μA. What vBE = 28VT is the correspo
laiz [17]

Answer:

Saturation current

Isi = 6.91 * 10^-17 A

The saturation current Is2 of transistor Q2 is 2.2 * 10-15 A

Collector current Ic2 at Vbe2 is 3.2mA

Base emitter voltage Vbe2 is 26.84 VT

Explanation:

Complete question is as follows;

Problem 6.3: In a particular technology, a small BJT operating at vBE = 28VT conducts a collector current of 100

µA. What is the corresponding saturation current?

For a transistor in the same technology but with an emitter junction that is 32 times larger, what is the saturation

current?

What current will this (second) transistor conduct at vBE = 28VT ?

What is the base-emitter voltage of the latter transistor at iC = 1 mA? Assume active-mode operation in all cases.

solution;

Please check attachment for complete solution and step by step explanation

4 0
3 years ago
What is discretization? What role does it play in finite element analysis?
ikadub [295]

Answer:

Discretization is the process in which elements are divided into the equivalent finite number. In discretization, variation occurs in different properties of the elements like force and materiel are applying in the input.

Each element in the discretization are associate with real physical response of the body. And it result in drastic change within the body then, discretization process is done.

Role of discretization in finite element analysis are:

The process of diving the elements in the equivalent number which are associated with the nodes. Then, the discretization in finite element method of an element are finite element analysis.

And the discretization process are basically depend upon the variation in the result. The smallest element produce the meaningful result in discretization.

4 0
3 years ago
In order to break even, your minimum selling price must be __________ your variable costs.
Gelneren [198K]
Your minimum selling price must be HIGHER THAN your variable costs
7 0
3 years ago
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