Answer:
(b) 10 Wb
Explanation:
Given;
angle of inclination of magnetic field, θ = 30°
initial area of the plane, A₁ = 1 m²
initial magnetic flux through the plane, Φ₁ = 5.0 Wb
Magnetic flux is given as;
Φ = BACosθ
where;
B is the strength of magnetic field
A is the area of the plane
θ is the angle of inclination
Φ₁ = BA₁Cosθ
5 = B(1 x cos30)
B = 5/(cos30)
B = 5.7735 T
Now calculate the magnetic flux through a 2.0 m² portion of the same plane
Φ₂ = BA₂Cosθ
Φ₂ = 5.7735 x 2 x cos30
Φ₂ = 10 Wb
Therefore, the magnetic flux through a 2.0 m² portion of the same plane is is 10 Wb.
Option "b"
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
Below are the choices that can be found from other sources:
<span>A) 29 mJ
B) 57 mJ
C) 10 mJ
D) 100 mJ
E) 570 mJ
</span>
The answer is A) 29 mJ
Argon because it is a noble gas
Due to the shape of the lens , parallel rays will be deviated