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cluponka [151]
3 years ago
15

What is the volume in liters at 422K if n and P does not change?

Chemistry
1 answer:
agasfer [191]3 years ago
8 0

Answer:

0.75 L

Explanation:

V1/T1 = V2/T2

V1 = 0.520 L

T1 = 18 C = 291 K (make sure to convert to Kelvin by adding 273 to the Celsius temperature)

V2 = ?

T2 = 422 K

Solve the equation for V2

V2 = V1T2/T1

V2 = (0.520 L)(422 K) / (291 K) = 0.754 L ≈ 0.75 L (since it says to only give two significant figures)

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What is true about the molar mass of chlorine gas? the molar mass is 35.5 g. the molar mass is 71.0 g. the molar mass is equal t
Bingel [31]

Chlorine gas, or dichlorine, is composed of 2 chlorine atoms and has a molar mass of 70.96, or about 71 g. So the answer is the molar mass is 71 g.

Hope this helps!

6 0
3 years ago
9. How do airbags protect the occupants of a car in a crash? Use the following words in
pentagon [3]
\textbf{Answer:}

Airbags are good for car crashes and have saved lots of life’s, the force of the airbags are dangerous though because they come out with fast acceleration and when it is hot it can burn you. If there is ever a time for collision airbags may save your live!

- ( I would appreciate if you gave brainliest if I helped you, if not please let me know what I got wrong! If you need any more help do not hesitate to ask! :) )

5 0
3 years ago
Na2CO3 + 2HCl ---------> 2NaCl + CO2 + H2O How many moles of NaCl are produced from the reaction of 1.67 x 1022 molecules of
dexar [7]

Answer:

0.0554 moles of NaCl are produced from the reaction of 1.67*10²² molecules of Na₂CO₃ with excess HCl.

Explanation:

The balanced reaction is:

Na₂CO₃ + 2 HCl → 2 NaCl + CO₂ + H₂O

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of each compound participate in the reaction:

  • Na₂CO₃: 1 mole
  • HCl: 2 moles
  • NaCl: 2 moles
  • CO₂: 1 mole
  • H₂O: 1 mole

On the other hand, Avogadro's Number is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023*10²³ particles per mole. Avogadro's number applies to any substance.

In this case, you can apply the following rule of three: if 6.023*10²³ molecules of Na₂CO₃ are contained in 1 mole, 1.67*10²² molecules will be contained in how many moles?

amount of moles=\frac{1.67*10^{22}molecules*1mole }{6.023*10^{23}molecules}

amount of moles= 0.0277 moles

In this case, you can apply the following rule of three: if by stoichiometry 1 mole of Na₂CO₃ produces 2 moles of NaCl, 0.0277 moles of Na₂CO₃ will produce how many moles of NaCl?

amount of moles of NaCl=\frac{0.0277 moles of Na_{2} CO_{3}*2 moles of NaCl }{1 mole of Na_{2} CO_{3}}

amount of moles of NaCl= 0.0554 moles

<u><em>0.0554 moles of NaCl are produced from the reaction of 1.67*10²² molecules of Na₂CO₃ with excess HCl.</em></u>

8 0
3 years ago
How many grams of aluminum are required to give a total dislocation length of 3,000 miles (enough to stretch from New York City
Luba_88 [7]

Answer:

0.13 g

Explanation:

mass of aluminum required = ( Dislocation length) / ( Dislocation density) × (density of metal)

3000 miles to cm (  1 mile = 160934 cm) = 3000 miles ×  160934 cm / 1 mile = 482802000 cm

density of Aluminium = 2.7 g /cm³

dislocation density of aluminum = 10¹⁰ cm³

mass of aluminum required = (482802000 cm × 2.7 g/cm³) / 10¹⁰ cm³ = 0.13 g

5 0
3 years ago
If you react 156.0 g of calcium chloride with an excess NaOH, how much sodium chloride should you get?
laiz [17]

Answer:

164.3g of NaCl

Explanation:

Based on the chemical equation:

CaCl2 + 2NaOH → 2NaCl + Ca(OH)2

<em>where 1 mole of CaCl2 reacts with 2 moles of NaOH</em>

To solve this question we must convert the mass of CaCl2 to moles. Using the chemical equation we can find the moles of NaCl and its mass:

<em>Moles CaCl2 -Molar mass: 110.98g/mol-</em>

156.0g CaCl₂ * (1mol / 110.98g) = 1.4057 moles CaCl2

<em>Moles NaCl:</em>

1.4057 moles CaCl2 * (2mol NaCl / 1mol CaCl2) = 2.811 moles NaCl

<em>Mass NaCl -Molar mass: 58.44g/mol-</em>

2.811 moles NaCl * (58.44g / mol) = 164.3g of NaCl

7 0
2 years ago
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