C6H6 is the
most insoluble in water as it is non polar in nature. HCL is highly soluble in
water as it is an electrolyte. Kbr is also highly soluble in water. NaCl
dissolves in water very quickly. CH3CH3OH is also totally soluble in water
because of the Hydrogen bonding formation. It is a well known fact that the
hydrocarbons do not easily mix with water. C6H6 being a strong hydrocarbon does
not mix with water. So among NaCl, KBr, CH3CH3OH, HCl and C6H6, the hydrocarbon
is the least soluble in water.
Answer B I believe
Not sure if it’s correct but Lina positive it is
Answer : The equilibrium concentration of is, 0.16 M
Explanation :
First we have to calculate the concentration of
and,
The given chemical reaction is:
Initial conc. 0.4 2.0 0
At eqm. (0.4-x) (2.0+x) x
The expression for equilibrium constant is:
Now put all the given values in this expression, we get:
x = -5.57 and x = 0.24
We are neglecting the value of x = -5.57 because equilibrium concentration can not be more than initial concentration.
Thus, the value of x = 0.24
The equilibrium concentration of = (0.4-x) = (0.4-0.24) = 0.16 M
Therefore, the equilibrium concentration of is, 0.16 M
Answer:
2 mol CH 4
Explanation:
43.8 x L
---------------- = 2 mol CH 4
22.4 x L x mol - 1
<span>ocean concentration of CO2 </span>