Answer:
CHANGE IN VOLUME -0.013 m3
Explanation:
given data:
we know that pressure remain constant for weighted piston cylinder
P1 =P2
Gas constant R = 259.81 j/Kg- K = 0.2598 kJ/kg K
mass, m1 =m2 = 0.01 kg
P1 = 20kPa
T1 = 100 degree C = 373 K
T2 = 0 degree C= 273 K
FROM IDEAL EQUATION
P1V1 =m RT1
V1 = 0.0484 m3
P2V2 =m RT2
V2 = 0.0.3546 m3
CHANGE IN VOLUME OS GIVEN
= 0.0354 - 0.0484
= -0.013 m3
Answer:
C
Explanation:
The answer is C - both technician A & B
Answer:
0.14% probability of observing more than 4 errors in the carpet
Explanation:
When we only have the mean, we use the Poisson distribution.
In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:
In which
x is the number of sucesses
e = 2.71828 is the Euler number
is the mean in the given interval.
The number of weaving errors in a twenty-foot by ten-foot roll of carpet has a mean of 0.8.
This means that
What is the probability of observing more than 4 errors in the carpet
Either we observe 4 or less errors, or we observe more than 4. The sum of the probabilities of these outcomes is 1. So
We want P(X > 4). Then
In which
0.14% probability of observing more than 4 errors in the carpet
Answer:
The force will be "125 N".
Explanation:
The given values are:
As we know,
⇒
then,
⇒
⇒
Since,
The pressure on both the pistons are equal, then
⇒
or,
⇒
By substituting the values, we get
⇒
⇒
⇒
⇒
⇒