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4vir4ik [10]
4 years ago
10

What do work and energy have in common

Physics
1 answer:
spayn [35]4 years ago
3 0

Energy and Work have the same unit of measurement which is Joules in SI units.

Explanation:

  • A Joule of Work is said to be done on an object when energy is transferred to that particular object.
  • If two objects are involved, when one object transfers energy onto the second, a joule of work is said to be done by the first object.  
  • Work is also the application of force on an object over a distance. So Work = Force × Displacement
  • Energy is neither created nor destroyed. It is in 2 forms - kinetic and potential.
  • Kinetic energy is defined as the energy of a moving object while potential energy is known as the energy that is stored within an object.
  • Kinetic Energy = 1/2 × mass × (velocity)²
  • Potential Energy = mass × acceleration due to gravity × height
  • Both energy and work are measured in Joules.
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If the tire reaches a temperature of 48 ∘c, what fraction of the original air must be removed if the original pressure of 250 kp
andrey2020 [161]
Assuming air as ideal gas and amount of air in no of moles is known then by gas law,

PV= nRT

Pressure is constant

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7 0
4 years ago
calcula la potencia por hora de un radiador, sabiendo que esta conectado a un contacto común 110 v. y requiere 20 Amp.
Ira Lisetskai [31]

calculate the power per hour of a radiator, knowing that it is connected to a common 110 v contact. and requires 20 Amp.

Answer:

2.2kWh

Explanation:

Given parameters:

Potential difference  = 110v

Current  = 20A

Unknown:

Power  = ?

Solution:

To solve this problem, we use the expression below:

        Power  = IV

 Power  = 110 x 20  = 2200W

  This is therefore 2.2kW

 Power per hour  = 2.2kWh

8 0
3 years ago
The battleship and enemy ships 1 and 2 lie along a straight line. Neglect air friction. battleship 1 2 Consider the motion of th
DaniilM [7]

Answer:

\frac{t_1}{t_2} = \frac{sin\theta_1}{sin\theta_2}

Explanation:

The vertical component of the initial velocities are

v_v = v_0sin\theta

If we ignore air resistance, and let g = -9.81 m/s2. The the time it takes for the projectiles to travel, vertically speaking, can be calculated in the following motion equation

v_vt - gt^2/2 = s = 0

t(v_v - gt/2) = 0

v_v - gt/2 = 0

t = 2v_v/g = 2v_0sin\theta/g

So the ratio of the times of the flights is

t_1 / t_2 = \frac{2v_0sin\theta_1/g}{2v_0sin\theta_2/g} = \frac{sin\theta_1}{sin\theta_2}

8 0
3 years ago
Lightning bolts can carry currents up to approximately 20 kA. We can model such a current as the equivalent of a very long, stra
GalinKa [24]

Answer:

how large a magnetic field would you experience = 8.16 x 10∧-4T

Explanation:

I = 20KA = 20,000A

r = 4.9 m

how large a magnetic field would you experience =  u.I/2πr

how large a magnetic field would you experience = (4π x10∧-7) × 20000/2π × 4.9

how large a magnetic field would you experience = 8.16 x 10∧-4T

4 0
3 years ago
Read 2 more answers
A satellite orbits the earth at a speed of 8.0x 10^3m/s . Calculate the period of orbit of the satellite if the distance between
gladu [14]

Hi there!

The period of an orbit can be found by:

T = \frac{2\pi r}{v}

T = Period (? s)
r = radius of orbit (6400000 m)

v = speed of the satellite (8000 m/s)

This is the same as the distance = vt equation. The total distance traveled by the satellite is the circumference of its circular orbit.

Let's plug in what we know and solve.

T = \frac{2\pi (6400000)}{8000} = \boxed{5026.55 s}

8 0
2 years ago
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