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zaharov [31]
3 years ago
7

What do the law of superposition and the law of inclusion have in common? (1 point) 1. Both laws are about matching fossils in d

ifferent areas. 2. Both laws give the exact ages of rocks. 3. Both laws describe the relative ages of rocks. 4. Both laws are about the ages of intruding rocks.
Physics
1 answer:
r-ruslan [8.4K]3 years ago
4 0

Answer:

its b

i took the test

Explanation:

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A volleyball player bumps a ball across a net with the velocity and angle shown below. What is the maximum height of the ball?
Marrrta [24]

Answer:

D. 12.4 m

Explanation:

Given that,

The initial velocity of the ball, u = 18 m/s

The angle at which the ball is projected, θ = 60°

The maximum height of the ball is given by the formula

                             h = u² sin²θ/2g  m

Where,

                           g - acceleration due to gravity. (9.8 m/s)

Substituting the values in the above equation

                            h = 18² · sin²60 / 2 x 9.8

                               = 18² x 0.75 / 2 x 9.8

                               = 12.4 m

Hence, the maximum height of the ball attained, h = 12.4 m

6 0
3 years ago
How would clearing a forest to plant corn affect an enviroment
Oksanka [162]
It would destroy animals homes shelter etc. it also would make global warming go faster. Hope this helped :D
4 0
2 years ago
Prior to determining the experimental design, a scientist typically? A. makes observations. B. forms a hypothesis. C. performs a
Umnica [9.8K]

Prior to determining the experimental design, a scientist typically forms a hypothesis. The answer is letter B. this is to prepare the scientist, the possible outcome of their research before the experimental design whether they are wrong or not.

7 0
2 years ago
What is the SPEED of a ball that travels 120 m in 6s?
AVprozaik [17]

Answer:

20m/second

Explanation:

The reason the answer is 20m/second is because to find the speed of the ball  in this question you have to divide the distance over the time giving you the result of 20m/second

7 0
3 years ago
An open organ pipe 30 cm long and a closed organ pipe 23 cm long, both of same diameter , are each sounding its first overtone ,
cupoosta [38]

First overtone of open organ pipe is given as

f_{1o} = \frac{v}{L_1 + 2e}

first overtone of closed organ pipe is given as

f_{1c} = \frac{3v}{4(L_2 + e)}

now they are in unison so we will have

\frac{v}{L_1 + 2e} = \frac{3v}{4(L_2 + e)}

\frac{1}{30 + 2e} = \frac{3}{4(23 + e)}

90 + 6e = 92 + 4e

e = 1 cm

so end correction of both pipes is e = 1 cm

8 0
2 years ago
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