All categories

2 years ago

A teacher moves a box of books weighting 25lbs a distance of 40ft. How much work has she done?

Chemistry

1 answer:

svp [43]2 years ago

6 0

Answer:

$workdone = weight \: \times \: distance \\ = 25 \times 40 \\ = 1000 \: lbsft \\ or \\ = 1000 \: joules$

You might be interested in

2AgNO3 + CaCl2 → 2AgCl + Ca(NO3)2

Harrizon [31]

It can be found that 337.5 g of AgCl formed from 100 g of silver nitrate and 258.4 g of AgCl from 100 g of CaCl₂.

<u>Explanation:</u>

2AgNO₃ + CaCl₂ → 2 AgCl + Ca(NO₃)₂

We have to find the amount of AgCl formed from 100 g of Silver nitrate by writing the expression.

$100 g \text { of } A g N O_{3} \times \frac{2 \text { mol } A g N O_{3}}{169.87 g A g N O_{3}} \times \frac{2 \text { mol } A g C l}{1 \text { mol } A g N O_{3}} \times \frac{143.32 g A g C l}{1 \text { mol } A g C l}$

= 337.5 g AgCl

In the same way, we can find the amount of silver chloride produced from 100 g of Calcium chloride.

It can be found as 258.4 g of AgCl produced from 100 g of Calcium chloride.

4 0

3 years ago

A gas sample has a temperature of 22c with an unknown volume. The same gas has a volume of 456 mL when the temperature is 86c wi

Mkey [24]

The initial volume is 116.65 mL

<u>Explanation:</u>

<u />

Given:

Temperature, T₁ = 22°C

T₂ = 86°C

Volume, V₂ = 456 m

V₁ = ?

According to Charle's law:

$\frac{V_1}{T_1} = \frac{V_2}{T_2}$

Substituting the values:

$\frac{V_1}{22} =\frac{456}{86} \\\\V_1 = \frac{456 X 22}{86} \\\\V_1 = 116.65 mL$

Therefore, the initial volume is 116.65 mL

3 0

2 years ago

ANSWER PLS ASAP Fireworks are an example of a<br> amount of energy being

Georgia [21]

Answer:

large, released

Explanation:

As we know, fireworks contain l o t s of energy, even before the burst of colors release. So i think choice 3 is the answer.

i hope this helps :)

3 0

2 years ago

What is the [OH-] if the [H3O+] is 1 x 10 -6?

Mariulka [41]

The answer is [OH⁻] = 1 x 10⁻⁸.

To find OH⁻, divide the ionic product of water by [H₃O⁺] as :

<u />

[OH⁻] = 1 x 10⁻¹⁴ / 1 x 10⁻⁶
[OH⁻] = 1 x 10⁻⁸

5 0

1 year ago

How much heat is lost when 1277 g of H20 at 400 K is changed into ice at 263 K? Plz help I’ll give you brainliest 20 points

OLga [1]

The heat lost is $-7.32*10^-^5J$

The heat lost when the ice is cooled from 400k to 263K can be calculated using the formula of heat transfer.

<h3>Heat Transfer</h3>

This is the heat transferred from a body of higher temperature to a body of lower temperature.

$Q = mc(\delta)T$

Q = Heat Transfer
m = mass = 1277g
ΔT = change in temperature

$\delta T = (400 - 273) - (263 - 273) = \\
\delta T = T_2 - T_1\\
\delta T = -10 - 127\\
\delta T = -137^0C$

We converted the temperature from kelvin scale into Celsius scale and find the change in temperature.

Solving for heat transfer

$Q = mc\delta T\\
Q = 1277 * 4.186 * -137\\
Q = -732336.514J$

The heat loss is approximately $-7.32*10^-^5J$

Learn more on heat transfer here;

brainly.com/question/16055406

6 0

2 years ago