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3 years ago

There are 4.184___ in a Joule of energy

Chemistry

1 answer:

Alinara [238K]3 years ago

4 0

Answer: calories?

Explanation: but isn’t it 1 calorie = 4.184 joules of energy

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2. The density of helium is 1.78 X 104 g/cm. What is this<br> density in Dg/um??

Zepler [3.9K]

Answer:

$d=1.78\times 10^{-7}\ Dg/\mu m^3$

Explanation:

Given,

The density of Helium is $1.78\times 10^4\ g/cm^3$

We need to find the density in Dg/μm

We know that,

1 g = 10 dg

1 cm³ = 10¹² μm³

So,

$d=1.78 \times 10^4\ g/cm^3\\\\=1.78 \times 10^4\times \dfrac{10\ dg}{10^{12}\ \mu m^3}\\\\=1.78\times 10^{-7}\ Dg/\mu m^3$

So, the density of Helium is equal to $1.78\times 10^{-7}\ Dg/\mu m^3$ .

4 0

2 years ago

Calculate the [oh−] in a solution with a ph of 12.52.

BaLLatris [955]

PH + pOH = 14

12.52 + pOH = 14

pOH = 14 - 12.52

pOH = 1.48

[OH⁻] = 10^ -pOH

[OH⁻] = 10 ^- 1.48

[OH⁻] = 0.033 M

6 0

3 years ago

The average speed of oxygen molecules in air is about ____. (1 point) 0 km/h 170 km/h 1700 km/h 17,000 km/h

LenKa [72]

The average speed is calculated using the following formula $speed = \sqrt{\frac{3kT}{m} }$

Where

$k = 1.381 X 10^{-23} J / K$

T = 298 K [room temperature]

m = mass of each molecule of oxygen

mass of one mole of oxygen molecules = 32 g / mol

mass of one molecule of oxygen will be = $\frac{32}{6.023 X 10^{23} }$

mass of one molecule of oxygen will be = $5.31 X 10^{-23} g = 5.31 X 10^{-26} kg$

putting values

average speed = $\sqrt{\frac{3 X 1.381 X 10^{-23} X 298}{5.31 X 10^{-26} kg} }$

Average speed = 482.19 m / s

average speed = 1735.8 km / h

so approx = 1700 km/h

4 0

3 years ago

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In chemical reaction atoms are what?

user100 [1]

Answer:

<h3>In chemical reaction atoms are reactants </h3>

5 0

3 years ago

The naturally occurring lactone Sedanenolide is the major contributor to the flavor of celery. Amend the structure below to show

Citrus2011 [14]

Answer:

[Find the diagram in the attachment]

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3 years ago

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