That's 1/2 of what it is on the surface.
The distance between the center of the Earth and any object
on the surface is 1 Earth radius ... about 3960 miles.
Gravitational force is inversely proportional to the square of
the distance between the centers of the objects, so in order
to reduce the acceleration of gravity by 1/2, you increase the
distance by √2 .
(3960 miles) x (√2) = 5,600 miles from the center
= 1,640 miles above the surface.
The Coulomb’s law is expressed mathematically as:
F = k * q1 * q2 / d^2
Where,
F = force of attraction between 2 particles = 2.0 N
<span> k = Coulomb’s
constant = 8.988 * 10^9 N m^2 / C^2</span>
q = charge of the particle
d = distance between the 2 particles = 1.35 m
Since the two coins have identical charges therefore q1 =
q2 =q
F = k* q^2 / d^2
2.0 N = (8.988 * 10^9 N m^2 / C^2) * q^2 / (1.35 m)^2
q =
2.01 * 10^-5 C
<span>Therefore each coins have charges equivalent to 2.01 *
10^-5 C.</span>
It's a law of nature, which I don't understand too well, that we can
cool things as close to Absolute Zero as we want to, but we can
never get all the way there.
I think that individual atoms and molecules have been cooled in
the laboratory to within a few thousandths of a Celsius degree
of it ... actually not too shabby an accomplishment !
____________________________________
WOW ! I just went and searched online for more information
on this subject. (You can't imagine what great stuff you can find
by doing that. You ought to try it some time.)
The 1997 Nobel Prize in Physics was awarded to a team of three
physicists who invented a method of using lasers to slow down the
motion of atoms, and that's the same thing as cooling them. They
were able to cool some atoms to a temperature of 240 millionths
of a degree above Absolute Zero !
<span>Acceleration is the rate of
change of the velocity of an object that is moving. This value is a result of
all the forces that is acting on an object which is described by Newton's
second law of motion. Calculations of such is straightforward, if we are given
the final velocity, the initial velocity and the total time interval. However, we are not given these values. We are only left by using the kinematic equation expressed as:
d = v0t + at^2/2
We cancel the term with v0 since it is initially at rest,
d = at^2/2
44 = a(6.2)^2/2
a = 2.3 m/s^2
</span>
