Answer:
B
Explanation:
A detailed solution to the problem is shown in the image attached. You could study it. The half life, and percentage of C-14 compared to present living sample was given as 13% of that of a living sample.
Answer:
Hey
Your answer is the one on the bottom
Newton's first law states that objects in motion will remain in motion (unless acted on by an external force) and that objects at rest will remain at rest.
On earth, if you throw a ball it will hit the ground and the friction between the grass and ball will slow it down. If the ground was frictionless then it would keep going forever.
ᴵ ʷʳᵒᵗᵉ ᵃˡˡ ᵗʰᵃᵗ^. ᶦ ᵈᵒⁿ'ᵗ ᶜᵒᵖʸ ᶠʳᵒᵐ ᵍᵒᵒᵈˡᵉ!
Hope it helped.
Answer:
![\rho = 3.68 *10^{-8} Ω. m](https://tex.z-dn.net/?f=%5Crho%20%3D%203.68%20%2A10%5E%7B-8%7D%20%CE%A9.%20m)
Explanation:
The resistance is given as
![R = \frac{\rho L}{A}](https://tex.z-dn.net/?f=R%20%3D%20%5Cfrac%7B%5Crho%20L%7D%7BA%7D)
Where A IS Cross sectional area of wire![= \pi r^{2}](https://tex.z-dn.net/?f=%3D%20%5Cpi%20r%5E%7B2%7D)
therefore resistivity \rho can be wrtten as
![\rho = \frac{\pi Rd^{2}}{4L}](https://tex.z-dn.net/?f=%5Crho%20%3D%20%5Cfrac%7B%5Cpi%20Rd%5E%7B2%7D%7D%7B4L%7D)
Putting all value to get resistivity value![\rho =\frac{\pi* 61*10^{-3}* (1.33*10^{-3})^{2}}{4*2.3}](https://tex.z-dn.net/?f=%5Crho%20%3D%5Cfrac%7B%5Cpi%2A%2061%2A10%5E%7B-3%7D%2A%20%281.33%2A10%5E%7B-3%7D%29%5E%7B2%7D%7D%7B4%2A2.3%7D)
![\rho = 3.68 *10^{-8} Ω. m](https://tex.z-dn.net/?f=%5Crho%20%3D%203.68%20%2A10%5E%7B-8%7D%20%CE%A9.%20m)