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Answer:
Magnitude of electric field = E = q/Aε0
Explanation:
Consider plates are placed at a distance of d. As given in the question the charge stored on the plates have magnitude q and given by:
q = CV
And
V = q/C ……. (i)
The capacitance is given by the following equation:
C = Aε0/d ……. (ii)
Put equation (ii) in (i)
,
V = qd/ Aε0 …..(iii)
The electric field is defined as:
E = V/d …… (iv)
Put equation (iii) in (iv),
E = qd/ Aε0d
E = q/Aε0
Hence, the magnitude of electric field will be q/Aε0 .
Answer:
Newton's second law of motion describes the relationship between force and acceleration. They are directly proportional. If you increase the force applied to an object, the acceleration of that object increases by the same factor. In short, force equals mass times acceleration.
Explanation:
