Answer:
a price war
Explanation:
An Oligopoly is when a small group of two or more companies dominates a market. Oligopoly firms may consent to market collusion, and create barriers to new commerce entry. If the businesses do not, they will probably be forced to lower their prices and open the market to new and smaller companies.
It is the type of competition between the company selling the similar type of product , or rival companies who tries to reduce the price of the product strategizing in a way to apprehend the wider area of the market , is known as a price war .
In the event one of the firms forming the oligopoly decides to lower prices, a price war occurs breaking the balance of the oligopoly and destabilizing the equilibrium of demand and supply in that market.
Reduction of the price of any goods or commodity is considered to be one of the best method to increase its market share ,because as soon as the price of any good decreases , the sales automatically increases , as the consumers are always in search of some discounts and good deals .
price war -
Answer:
A solid material whose constituents (such as atoms, molecules, or ions) are arranged in a highly ordered microscopic structure, forming a crystal lattice that extends in all directions.
Explanation:
francium , in the Periodic table the atomic radius increases from top to bottom in a group, and decreases from left to right across a period. making helium is the smallest element, and francium the largest.
We have that all (ideal) gases obey the fundamental gas equation: PV=nRT where P is the Pressure, V is the Volume, n is the number of moles, R is a universal constant and T is the temperature in Kelvin. In this process, we have that both the number of moles and the temperature stays the same. So if we denote by i the initial conditions and by f the final conditions of the gas, we have:
. Hence, if we solve for the final Volume we get:
. Now we know all the other variables; substituting we get that the final volume is 6.7 L (6.716 L ).
Answer:
(a)
(b)
Explanation:
Hello,
(a) In this case, as the reaction is second-ordered, one uses the following kinetic equation to compute the concentration of NOBr after 22 seconds:
![\frac{1}{[NOBr]}=kt +\frac{1}{[NOBr]_0}\\\frac{1}{[NOBr]}=\frac{0.8}{M*s}*22s+\frac{1}{0.086M}=\frac{29.3}{M}\\](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B%5BNOBr%5D%7D%3Dkt%20%2B%5Cfrac%7B1%7D%7B%5BNOBr%5D_0%7D%5C%5C%5Cfrac%7B1%7D%7B%5BNOBr%5D%7D%3D%5Cfrac%7B0.8%7D%7BM%2As%7D%2A22s%2B%5Cfrac%7B1%7D%7B0.086M%7D%3D%5Cfrac%7B29.3%7D%7BM%7D%5C%5C)
![[NOBr]=\frac{1}{29.2/M}=0.0342M](https://tex.z-dn.net/?f=%5BNOBr%5D%3D%5Cfrac%7B1%7D%7B29.2%2FM%7D%3D0.0342M)
(b) Now, for a second-order reaction, the half-life is computed as shown below:
![t_{1/2}=\frac{1}{k[NOBr]_0}](https://tex.z-dn.net/?f=t_%7B1%2F2%7D%3D%5Cfrac%7B1%7D%7Bk%5BNOBr%5D_0%7D)
Therefore, for the given initial concentrations one obtains:
Best regards.
