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goldfiish [28.3K]
3 years ago
9

For a theoretical yield of 2.97 g and percent yield of 93.4452%, calculate the actual yield for a chemical reaction. Answer in u

nits of g.
Chemistry
1 answer:
MariettaO [177]3 years ago
3 0

Answer:

2.77532244 grams

Explanation:

Percent yeild=actual/theoretical * 100

Plug in the values

93.4452=actual/2.97 *100

0.934452*2.97=2.77532244

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a flask contains 2 gases. the first gas has a pressure of 0.76 atm and the second gas gas a pressure of 4,500 Pa. what is the to
Liula [17]

Answer:

The total pressure is 0,804 atm

Explanation:

We use Dalton's law according to which the sum of the partial pressures is equal to the total pressure of a gas mixture. We convert the pressure in Pascals to atmosphere (it can also be done in reverse):

101300Pa ----1 atm

4500Pa----x= (4500Pa x 1atm)/101300Pa= 0,044 atm

P total= p1 + p2= 0,76 atm + 0,044 atm=0,804 atm

4 0
3 years ago
A 0.35 L balloon found at 19 C is heated in an oven to 250 C. What is the new volume of the balloon?
Svet_ta [14]

Answer:

V = 0.63 L

Explanation:

To solve this problem, we need to use the Charle's law which is a law that involves temperature and volume, assuming we have a constant pressure. The problem do not state that the pressure is being altered, so we can safely assume that the pressure is constant (Maybe 1 atm).

Now, as the pressure is constant, the Charle's law is the following:

V₁ / T₁ = V₂ / T₂   (1)   V is volume in Liter, and T is temperature in Kelvin.

Using this law with the given data, we solve for V₂:

V₂ = V₁T₂ / T₁

Before we use this expression, let's convert the temperatures to Kelvin:

T₁ = 19 + 273 = 292 K

T₂ = 250 + 273 = 523 K

Now, let's calculate the volume of the balloon:

V₂ = 0.35 * 523 / 292

<h2>V₂ = 0.63 L</h2>
5 0
3 years ago
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ira [324]

Answer:

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4 0
2 years ago
How many grams of sodium carbonate are produced when 5.3 moles of sodium phosphate reacts with aluminum carbonate?
Korvikt [17]

Answer: There is 842.54 grams of sodium carbonate are produced when 5.3 moles of sodium phosphate reacts with aluminum carbonate.

Explanation:

Chemical equation depicting reaction between sodium phosphate and aluminum carbonate is as follows.

Al_{2}(CO_{3})_{3} + 2Na_{3}PO_{4} \rightarrow 2AlPO_{4} + 3Na_{2}CO_{3}

As this equation contains same number of atoms on both reactant and product side. So, this equation is a balanced equation.

According to the equation, 2 moles of sodium phosphate is giving 3 moles of sodium carbonate.

Therefore, sodium carbonate formed by 5.3 moles of sodium phosphate is as follows.

\frac{3}{2} \times 5.3 mol\\= 7.95 mol

As number of moles is the mass of substance divided by its molar mass. So, mass of sodium carbonate ( molar mass = 105.98 g/mol) is as follows.

No. of moles = \frac{mass}{molar mass}\\7.95 mol = \frac{mass}{105.98 g/mol}\\mass = 842.54 g

Thus, we can conclude that there is 842.54 grams of sodium carbonate are produced when 5.3 moles of sodium phosphate reacts with aluminum carbonate.

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3 years ago
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