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3 years ago

Why can't copper sulphate be prepared by adding copper metal to dilute sulphuric acid

Chemistry

1 answer:

Crank3 years ago

4 0

Answer:

Copper metal will not react with sulfuric acid . ( Copper metal is too unreactive / it is " below hydrogen in the reactivity series " ). So use copper carbonate, it reacts easily to give copper sulfate ( and carbon dioxide and water ) .

Explanation:

i hope it's help you

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What does the pacific tsunami warning system use to detect tsunamis ?

S_A_V [24]

Answer:

Explanation:

Their are pressure sensers in the water that will detect high pressure and set of scales that are currently detecting semic waves and trigger sierns.

7 0

2 years ago

PLEASE HELP ME! THANK YOU IF YOU DO!!! ^^

frozen [14]

Answer:

oceanic formation is the right answer.

Explanation:

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2 years ago

Find the enthalpy of neutralization of HCl and NaOH. 137 cm3 of 2.6 mol dm-3 hydrochloric acid was neutralized by 137 cm3 of 2.6

liraira [26]

Answer : The correct option is, (D) 89.39 KJ/mole

Explanation :

First we have to calculate the moles of HCl and NaOH.

$\text{Moles of HCl}=\text{Concentration of HCl}\times \text{Volume of solution}=2.6mole/L\times 0.137L=0.3562mole$

$\text{Moles of NaOH}=\text{Concentration of NaOH}\times \text{Volume of solution}=2.6mole/L\times 0.137L=0.3562mole$

The balanced chemical reaction will be,

$HCl+NaOH\rightarrow NaCl+H_2O$

From the balanced reaction we conclude that,

As, 1 mole of HCl neutralizes by 1 mole of NaOH

So, 0.3562 mole of HCl neutralizes by 0.3562 mole of NaOH

Thus, the number of neutralized moles = 0.3562 mole

Now we have to calculate the mass of water.

As we know that the density of water is 1 g/ml. So, the mass of water will be:

The volume of water = $137ml+137ml=274ml$

$\text{Mass of water}=\text{Density of water}\times \text{Volume of water}=1g/ml\times 274ml=274g$

Now we have to calculate the heat absorbed during the reaction.

$q=m\times c\times (T_{final}-T_{initial})$

where,

q = heat absorbed = ?

$c$ = specific heat of water = $4.18J/g^oC$

m = mass of water = 274 g

$T_{final}$ = final temperature of water = 325.8 K

$T_{initial}$ = initial temperature of metal = 298 K

Now put all the given values in the above formula, we get:

$q=274g\times 4.18J/g^oC\times (325.8-298)K$

$q=31839.896J=31.84KJ$

Thus, the heat released during the neutralization = -31.84 KJ

Now we have to calculate the enthalpy of neutralization.

$\Delta H=\frac{q}{n}$

where,

$\Delta H$ = enthalpy of neutralization = ?

q = heat released = -31.84 KJ

n = number of moles used in neutralization = 0.3562 mole

$\Delta H=\frac{-31.84KJ}{0.3562mole}=-89.39KJ/mole$

The negative sign indicate the heat released during the reaction.

Therefore, the enthalpy of neutralization is, 89.39 KJ/mole

3 0

3 years ago

What is the difference between chemical and physical change with respect

kozerog [31]

Answer:

Physical changes are changes that do not alter the identity of a substance. Chemical changes are changes that occur when one substance is turned into another substance.

Explanation:

5 0

2 years ago

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PLEASE HELP ME!!

mrs_skeptik [129]

Answer:

The answer to this question is D.

Explanation: We know that only plants have a cell wall so that is helpful and we know that plants are green because of their chloroplast. So the answer is D, cell wall, and chloroplast.

6 0

2 years ago

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