To calculate and solve the problem it is necessary to apply the concepts related to resistance and resistivity.
The equation that is responsible for relating the two variables is:
Where,
R= Resistance of the conductor
Resistivity of the conductor material
L = Length
A = Cross-sectional area of conductor
With the previous values the area of the muscle (Real Muscle-82%)is,
Using the equation from Resistance we have that at the muscle the value is:
At the same time we can make the same process to calculate the resistance of the fat, then
The resistance of the fat would be,
Then the total resistance in a set as the previously writen, i.e, in parallel is:
We can here apply Ohm's law, then
having to push a rough and heavy box across the floor to move it
Explanation:
Friction is not a useful force because we have to exert even more force to push a body that is rough and heavy across the floor to move it.
- Frictional force is a force that opposes the motion of a body.
- It costs more and uses more energy to push a rough and heavy box on surface because of friction.
- This wastes energy in systems that deals with pushing.
Friction is useful in that:
- the heat energy produced when two surfaces rub together is very useful.
- the friction between your feet and the floor keeping you from slipping and makes walking possible.
- the tread on tires helping the moving vehicle slow down and stop when necessary.
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Answer:
16.7 mF
Explanation:
The total capacitance of two capacitors connected in series is given by the formula:
in our problem, we have:
C1 = 45 mF is the capacitance of the first capacitor
C2 = 26 mF is the capacitance of the second capacitor
Substituting into the equation, we find:
So the equation used in this problem is ΔX=V0*T+1/2AT^2 the X is the distance, v0 is initial velocity, T is time, and a is acceleration. So when we plug these values it we get: 108= 0•T+1/2•3•T^2,the 0•t disappears, and the 1/2•3 gets us 1.5, so we have 108=1.5T^2, then we divide 108 by 1.5 which gets us 72=t^2, and we then take the square root and get 8.49=T so the answer is 8.49 seconds.
Answer:
Before:
After:
Explanation:
<u>Conservation of Momentum</u>
Two objects of masses m1 and m2 moving at speeds v1o and v2o respectively have a total momentum of
After the collision, they have speeds of v1f and v2f and the total momentum is
Impulse J is defined as
Where F is the average impact force and t is the time it lasted
Also, the impulse is equal to the change of momentum
As the total momentum is conserved:
We can compute the speed of the second object by solving the above equation for v2f
The given data is
a) The impulse will be computed at the very end of the answer
b) Before the collision
c) After collision
Compute the car's speed:
And the car's momentum is
The Impulse J of the system is zero because the total momentum is conserved, i.e. \Delta p=0.
We can compute the impulse for each object
The force can be computed as
The force on the car has the same magnitude and opposite sign
