Question

A student connects three AA batteries (1.5 V each) in series to light up a light bulb. The circuit has a resistance of 35 Ω. How much current flows through the circuit?
A.
52.5 A

B.
0.13 A

C.
157.5 A

D.
0.04 A

Answer 1

Answer:

0.13A

Explanation:

Given parameters:

Number of batteries  = 3

Voltage of each batter  = 1.5V

Voltage of the circuit  = 3 x 1.5  = 4.5V

Resistance  = 35Ω

Unknown:

Current that flows in the circuit  = ?

Solution:

According to Ohm's law;

             I  = $\frac{V}{R}$  

I is the current

V is the voltage

R is the resistance

 Now insert the parameters and solve;

             I  = $\frac{4.5}{35}$   = 0.13A