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kkurt [141]
3 years ago
11

A construction worker pushes a wheelbarrow 15 m with a horizontal force of 17 N. How much work is done by the worker on the obje

ct?
Physics
1 answer:
aivan3 [116]3 years ago
7 0

Answer:

The work done by the worker on the object is 255 J

Explanation:

Work is defined as the force that is applied on a body to move it from one point to another.

When a net force is applied to the body or a system and this produces displacement, then that force is said to perform mechanical work. This work can be positive if the system gains energy or negative if the system loses energy.

In the International System of Units, work is measured in Joule. Joule is equivalent to Newton per meter.

The work is equal to the product of the force by the distance and by the cosine of the angle that exists between the direction of the force and the direction that travels the point or the object that moves.  

In this case, the angle between the force and the displacement is 0 degrees. Then the cosine of 0 degrees will have a value of one. So work is calculated as the multiplication between force and distance:

W= 17 N* 15 m

Solving:

W= 255 J

<u><em>The work done by the worker on the object is 255 J</em></u>

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