HELP PLEASE...Arnold built a machine to help deliver the morning paper.He had to pull with 38N of force to move a stack of paper
1 answer:
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I will assume here that the well is sufficiently short so that the time the sound takes to come from the bottom of the well to our ear is negligible.
Since the pebble moves by uniformly accelerated motion, the distance it covers is given by
where
is the gravitational acceleration
is the time the pebble takes to reach the bottom of the well
Therefore, the depth of the well is
and the correct answer is B.
Since the pebble moves by uniformly accelerated motion, the distance it covers is given by
where
Therefore, the depth of the well is
and the correct answer is B.
Answer:
Therefore, the force supported by the hydraulic cylinder is = -70.01 lb
Thus, the force supported by the bar = -233.84 lb
The reaction force supported by the reaction of the roller = 341.31 lb
Explanation:
The attached diagrams is shown in the file below:
From there; taking moments about point A
- 40 (180) - (80) Cos 37° + 55
-7200 + (-80 Cos 37° + 55 sin 37° ) = 0
= - 7200 - 30.79
- 30.79 = 7200
=
= -233.84 lb
Thus, the force supported by the bar = -233.84 lb
Taking the equilibrium of forces in the vertical direction
sin 37 +
cos 20 -
= 0
- 233.84 sin 37 + cos 20 - 180 = 0
cos 20 = 320.73
=
= 341.31 lb
The reaction force supported by the reaction of the roller = 341.31 lb
Taking the equilibrium of forces on the horizontal direction.
cos 37 -
sin 20° = 0
-233.84 cos 37 - + 341.31 sin 20° = 0
-186.75 - + 116.74 = 0
- -70.01 = 0
- = 70.01
= - 70.01 lb
Therefore, the force supported by the hydraulic cylinder is = -70.01 lb
