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Anit [1.1K]
2 years ago
13

9. A mouse has a mass of 0. 4kg. What is its weight? (acceleration due to gravity on Earth is 9.8m/s2 = g)

Physics
1 answer:
Alik [6]2 years ago
8 0

Answer:

Weight = 3.92 N

Explanation:

Given:

Mass m = 0.4 kg

Acceleration due to gravity g = 9.8 m/s²

Find:

Weight

Computation:

Weight = Mass x Acceleration due to gravity

Weight = 0.4 x 9.8

Weight = 3.92 N

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If you shine a single light source on a screen you will see that the entire screen is lit up. Assume this light source is of a s
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An interference pattern.

Explanation:

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3 years ago
Un automóvil se mueve 80 m en 40 s con una velocidad constante. ¿Cuál es la velocidad del automóvil? Ayuda plissssssssssssssssss
Alexxandr [17]

Answer:

Velocidad = 2 m/s

Explanation:

Dados los siguientes datos;

Distancia = 80 m

Tiempo = 40 s

Para encontrar la velocidad del automóvil;

La velocidad se puede definir como la tasa de cambio en el desplazamiento (distancia) con el tiempo.

La velocidad es una cantidad vectorial y, como tal, tiene magnitud y dirección.

Matemáticamente, la velocidad viene dada por la ecuación;

Velocidad = \frac {distancia} {tiempo}

Sustituyendo en la fórmula, tenemos;

Velocidad = 80/40

Velocidad = 2 m/s

5 0
3 years ago
A block is released from rest, at a height h, and allowed to slide down an inclined plane. There is friction on the plane. At th
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Here the block has two work done on it

1. Work done by gravity

2. Work done by friction force

So here it start from height "h" and then again raise to height hA after compressing the spring

So work done by the gravity is given as

W_g = m_A g(h - h_A)

Now work done by the friction force is to be calculated by finding total path length because friction force is a non conservative force and its work depends on total path

W_f = -(\mu m_A g cos\theta)(\frac{h}{sin\theta} + \frac{h_A}{sin\theta})

W_f = -\mu m_A g cot\theta(h + h_A)

Total work done on it

W = m_A g(h - h_A) - \mu m_A g cot\theta(h + h_A)

So answer will be

None of these

7 0
3 years ago
Read 2 more answers
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