Ammonium hydroxide is considered a weak base because it produces few hydroxide ions in aqueous solution. (Option a)
<h3>Strength of electrolytes</h3>
- Strong electrolytes: are completely ionized in aqueous solution.
- Weak electrolytes: are partially ionized in aqueous solution.
Let's consider the ionization of ammonium hydroxide, which is a weak base.
NH₄OH ⇄ NH₄⁺ + OH⁻
Why is it considered a weak base?
a. it produces few hydroxide ions in aqueous solution. Yes, since it dissociates partially.
b. it produces few hydrogen ions in aqueous solution. No, since it does not produce hydrogen ions.
c. it does not conduct electricity in aqueous solution. No, since it conducts electricity, although poorly.
d. it will not take part in a neutralization reaction. No, since it will be neutralized by acids.
Ammonium hydroxide is considered a weak base because it produces few hydroxide ions in aqueous solution.
Learn more about weak bases here: brainly.com/question/322250
#SPJ1
Answer:
pH = 6.82
Explanation:
To solve this problem we can use the<em> Henderson-Hasselbach equation</em>:
- pH = pKa + log
![\frac{[NaOCl]}{[HOCl]}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BNaOCl%5D%7D%7B%5BHOCl%5D%7D)
We're given all the required data to <u>calculate the original pH of the buffer before 0.341 mol of HCl are added</u>:
- pKa = -log(Ka) = -log(2.9x10⁻⁸) = 7.54
- [HOCl] = [NaOCl] = 0.500 mol / 0.125 L = 4 M
- pH = 7.54 + log
By adding HCl, w<em>e simultaneously </em><u><em>increase the number of HOCl</em></u><em> and </em><u><em>decrease NaOCl</em></u>:
- pH = 7.54 + log
![\frac{[NaOCl-HCl]}{[HOCl+HCl]}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BNaOCl-HCl%5D%7D%7B%5BHOCl%2BHCl%5D%7D)
- pH = 7.54 + log
Answer: 3.97 moles HCl
Explanation: Solution:
2.39x10²⁴ atoms HCl x 1 mole HCl /
6.022x10²³ atoms HCl
= 3.97 moles HCl
Answer:
1 oxygen 1 hydrogen hydrogen peroxide I think
<span>S-shadows tells that the earths interior is liquid.</span>
