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const2013 [10]
3 years ago
13

What is different about what happens to a weak acid molecule and what happens to a strong acid molecule how does the PH or the a

mount of H3O change
Chemistry
1 answer:
Ber [7]3 years ago
7 0

Answer:

A weak acid will partially dissociate. A strong acid will almost completely dissociate.

Explanation:

This means that the H+ will "fall" off of the molecule and bind to H2O, forming H3O+

The pH will drop regardless, but moreso for a strong acid, as the H3O content rises, also moreso for a strong acid.

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How many grams are there in 3.30x10 23 grams of n2i6
qwelly [4]
Technically, the answer should be 3.30 * 10^23 grams. But I think you mean either molecules, atoms, moles or grams of Ni2I6 with that number of molecules .

1 mole of Ni2 I6  = 6.02 * 10^23 molecules
x  [mole] = 3.30 * 10^23 molecules

1/x = 6.02 * 10^23 / 3.30 * 10^23 Cancel the 10^23 on the right side
1/x = 6.02 / 3.30 Cross multiply
3.30 = 6.02 x Divide by 6.02
3.30 / 6.02 = x 
x = 0.548 moles 

what to do from here?

1 mole of Ni2I6 is
2 * Ni = 2 * 59 = 118 grams
6 *  I = 6 * 131 = <u>786 grams</u>
Total  =               904 grams

Set up a proportion.
<u>1 mole Ni2I6 </u>  = <u>904 grams</u>  
0.548 moles    = x

1/0.548 = 904/x Cross multiply
x = 0.548 * 904
x = 495.4 grams of Ni2I6 <<<<<< Answer.

8 0
4 years ago
How does the sky appear blue? (BONUS QUESTION)!!!!
crimeas [40]
This was an answer i found on google from Nasa

6 0
4 years ago
Read 2 more answers
What type of charge does each part of an atom have (positive, negative, no charge)
Masteriza [31]
Answer:
P-positive
N-negative
E-no charge
6 0
3 years ago
Read 2 more answers
Given 7.40 g of butanoic acid and excess ethanol, how many grams of ethyl butyrate would be synthesized, assuming a complete 100
Dafna11 [192]
On complete conversion (100% yield) 9.75 g of ethyl butyrate will be produced. Below is the solution.....

4 0
4 years ago
The radioactive decay of a certain sample produced 846 disintegrations per minute. exactly 3.00 days later, the rate of decay wa
Margarita [4]

Answer:

\boxed{\text{1.81 da}}

Explanation:

1. Calculate the decay constant

The integrated rate law for radioactive decay is 1

\ln\dfrac{A_{0}}{A_{t}} = kt

where

A₀ and A_t are the counts at t = 0 and t

k is the radioactive decay constant

\ln \dfrac{846}{269} = k \times 3.00\\\\\ln3.145 = 3.00k\\1.146 = 3.00k\\\\k =\dfrac{1.146}{3}\\\\k = \text{0.382 /da}\\

2. Calculate the half-life

t_{\frac{1}{2}} = \dfrac{\ln2}{k} = \dfrac{\ln2}{0.382} = \text{1.81 da}

The half-life for decay is \boxed{\textbf{1.81 da}}.

3 0
4 years ago
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