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2 years ago

Calculate the number of moles of iodine in 7.68×10^25 molecules of I2

Chemistry

1 answer:

Dmitrij [34]2 years ago

4 0

Answer:

<h2>127.57 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

$n = \frac{N}{L} \\$

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

$n = \frac{7.68 \times {10}^{25} }{6.02 \times {10}^{23} } \\ = 127.574750...$

We have the final answer as

<h3>127.57 moles</h3>

Hope this helps you

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Match each element to the number of electrons in its valence shell

blondinia [14]

Answer: Be= 2, C =4, Li = 1 and B=3

Explanation:

The valence shell can be define as the outermost shell of an atom that contains the valence electrons.

Beryllium (Be), electronic configuration; 1s2 2s2, = 2 electrons in its valence shell.

Carbon (C), electronic configuration; 1s2 2s2 2p2, = 4 electrons in its valence shell.

Lithium (Li), electronic configuration; 1s2 2s1 = 1 electron in its valence shell.

Boron (B) , electronic configuration; 1s2 2s2 2p1 = 3 electron in its valence shell.

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3 years ago

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2 years ago

What volume of so2 is produced at 325 k and 1.35 atm when 15.0 grams of hcl reacts with excess k2so3?

vova2212 [387]

The volume of SO2 produced at 325k is calculated as below

calculate the moles of SO2 produced which is calculated as follows

write the reacting equation
K2SO3 +2 HCl = 2KCl +H2O+ SO2

find the moles of HCl used
=mass/molar mass = 15g/ 36.5 g/mol =0.411 moles

by use of mole ratio between HCl to SO2 which is 2:1 the moles of SO2 is therefore = 0.411 /2 =0.206 moles of SO2

use the idea gas equation to calculate the volume SO2
that is V=nRT/P
where n=0.206 moles
R(gas constant) = 0.082 L.atm/ mol.k
T=325 K
P=1.35 atm

V=(0.206 moles x 0.082 L.atm/mol.k x325 k)/1.35 atm = 4.07 L of SO2

3 0

2 years ago

One mole of a metallic oxide reacts with one mole of hydrogen to produce two moles of the pure metal

kenny6666 [7]

Answer:

Lithium oxide, Li₂O.

Explanation:

Hello!

In this case, according to the given amounts, it is possible to write down the chemical reaction as shown below:

$M_2O+H_2\rightarrow 2M+H_2O$

Which means that the metallic oxide has the following formula: M₂O. Next, we can set up the following proportional factors according to the chemical reaction:

$5.00gM_2O*\frac{1molM_2O}{(2*X+16)gM_2O}*\frac{2molM}{1molM_2O}*\frac{XgM}{1molM}=2.32gM$