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seraphim [82]
2 years ago
7

What is the noble gas electron configuration for the element oxygen?

Chemistry
2 answers:
Daniel [21]2 years ago
8 0

[He] 2s² 2p⁴

Explanation:

just look it up

nika2105 [10]2 years ago
3 0

Answer:

[He] 2s² 2p⁴.................

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mixas84 [53]

Answer: Dynamic equilibrium

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2 years ago
Calculate the relative formula mass (Mr) of gold chloride (AuCl3).
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Answer:

197 + (35.5×3) = 303.5

Explanation:

relative formula mass is the sum of the relative atomic masses of the atoms in the formula ( AuCl3 )

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3 years ago
How can we find the volume of this fish tank? Please I needed but Good
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3 0
3 years ago
Read 2 more answers
PLEASE HELP!!!!!!!
dsp73

Answer: 1. 2Al+3CuCl_2\rightarrow 2AlCl_3+3Cu

2. 3 moles of CuCl_2 : 2 moles of Al

3. 0.33 moles of CuCl_2 : 0.92 moles of Al

4. CuCl_2 is the limiting reagent and Al is the excess reagent.

5. Theoretical yield of AlCl_3 is 29.3 g

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of} Al=\frac{25.0g}{27g/mol}=0.92moles

\text{Moles of} CuCl_2=\frac{45.0g}{134g/mol}=0.33moles

The balanced chemical equation is:

2Al+3CuCl_2\rightarrow 2AlCl_3+3Cu  

According to stoichiometry :

3 moles of CuCl_2 require = 2 moles of Al

Thus 0.33 moles of CuCl_2 will require=\frac{2}{3}\times 0.33=0.22moles  of Al

Thus CuCl_2 is the limiting reagent as it limits the formation of product and Al is the excess reagent.

As 3 moles of CuCl_2 give = 2 moles of AlCl_3

Thus 0.33 moles of CuCl_2 give =\frac{2}{3}\times 0.33=0.22moles  of AlCl_3

Theoretical yield of AlCl_3=moles\times {\text {Molar mass}}=0.22moles\times 133.34g/mol=29.3

Thus 29.3 g of aluminium chloride is formed.

5 0
2 years ago
Calculate the molar mass of Co2
olga nikolaevna [1]

Answer:

44.01 g/mol

Explanation:

Add each elements atomic mass. For oxygen you will do that twice because their is two oxygens.

- Hope that helps! Please let me know if you need further explanation.

8 0
2 years ago
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