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erastova [34]
2 years ago
9

How many Joules of heat would be required

Chemistry
1 answer:
mote1985 [20]2 years ago
4 0

Heat would be required  : 1,670 J

<h3>Further explanation</h3>

Given

mass of H₂O=5 g

Required

Heat to melt

Solution

The heat to change the phase can be formulated :

Q = m.Lf (melting/freezing)

Lf=latent heat of fusion

The heat of fusion for water at 0 °C : 334 J/g

Input given values in formula :

\tt Q=5\times 334=\boxed{\bold{1,670~J}}

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What is the reaction of guanine and adenine
PtichkaEL [24]

Complementary Base Pairing. Specific pairs can only go together, so when guanine and adenine pair up, its Complementry Base Pairing :)

Hope this helps! Please correct me if im wrong :)

5 0
2 years ago
Read 2 more answers
21 mL It required 42.35 mL of H2SO4 to neutralize 21.17 mL of 0.5000 M NaOH. Calculate the concentration of H2SO4
bija089 [108]
The balanced equation for the above reaction is 
2NaOH + H₂SO₄ ---> Na₂SO₄ + 2H₂O
stoichiometry of NaOH to H₂SO₄ is 2:1
number of NaOH moles required-0.5000 M / 1000 mL/L x 21.17 mL = 0.010585 mol
According to stoichiometry, acid moles required are 1/2 of the base moles reacted
Therefore number of H₂SO₄ moles reacted - 0.010585 /2  mol
Number of moles in 42.35 mL of H₂SO₄ - 0.010585 /2 mol
Therefore in 1 L solution - (0.010585) /2 / 42.35 mL x 1000 mL/L = 0.125 M
Molarity of H₂SO₄ - 0.125 M
5 0
3 years ago
Rn-222 has a half-life of 3.82 days. If 25.0 g of Radon-22 was originally present, approximately how many grams would be left af
horsena [70]

Answer:

Approximately 0.39 g or 0.4 g if you're rounding up

Explanation:

15/3.82 = 3.92

Let's round that up to 4

That means 15 days is around 4 half lives

4 half lives means 1/16 of the original mass will be left

25/16 = 0.390625

6 0
3 years ago
To a 0.0001 m solution of mg(no3)2, naoh was added to a final concentration of 0.001m did a precipitate form?
Natalija [7]

I looked on a solubility chart to answer this question, and hydroxides are generally insoluble (with some exceptions of course). However, it says to consider Mg(OH)_{2} as an insoluble substance, though it may be moderately soluble.


The answer that you are most likely looking for is: Yes, a precipitate does form - this is due to the double placement reaction:


Mg(NO_{3})_{2}_{(aq)} + 2NaOH_{(aq)} → Mg(OH)_{2} {(s)} + 2NaNO_{3}_{(aq)}

8 0
3 years ago
How many grams of sodium chloride are contained in 250.0 g of a 15% NaCl solution?
kramer

Given concentration of NaCl=15%

Means ,

In every 100g of Solution 15g of NaCl is present .

Now

  • Given mass=250g

So ,

\\ \Large\sf\longmapsto 250\times 15\%

\\ \Large\sf\longmapsto 250\times \dfrac{15}{100}

\\ \Large\sf\longmapsto 37.5g

<u>37.5g of NaCl present in 250g of solution.</u>

8 0
2 years ago
Read 2 more answers
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