Answer: The correct option would be A.
Explanation: The main group elements which make more bonds than that was predicted from the octet rule are supposed to have expanded octet.
These elements tend to have more than 8 valence electrons after bonding and this can be achieved when we have empty d-orbitals.
When we have empty p-orbitals, total number of valence electrons than can be occupied will be 8.
Electronic configuration when valence shell's empty p-orbitals are fully filled = 
which means that a total of 8 electrons can be occupied which does not satisfy expanded octet rule.
Example of molecule showing expanded octet rule is given in the image. Here, after bonding Phosphorous has 10 electrons which is occupied in empty d-orbitals.
4.48
pH=pKa+log([A-/HA])
25% deprotonated tells us that A- is .25 and that the rest (75% is protonated) thats .75.
4 = pKa + log \frac{.25}{.75}
4 - log \frac{.25}{.75} = pKa
4.48=pKa
Answer:
52.00 AMU
Explanation:
(49.946 * 0.043) + (51.941 * 0.838) + (52.941 * 0.095) + (53.939 * 0.024) = 51.998
Make sure to round, 52.00 AMU.
Answer:
Kyanite (Al2SiO5) - silicate
Ilmenite (FeTiO3) - Oxides
Rhodochrosite (MnCO3) - carbonate
Celestite (SrSO4) - sulphate
Chalcocite (Cu2S) - sulphide
Explanation:
Minerals are classified according to their chemical composition. For example those that hve the CO32- ion are called carbonates and those with the SO42- ion are called sulphates while the ones with S2- ion are called sulphides
Answer:
d = 0.98 g/L
Explanation:
Given data:
Density of acetylene = ?
Pressure = 0.910 atm
Temperature = 20°C (20+273 = 293 K)
Solution:
Formula:
PM = dRT
R = general gas constant = 0.0821 atm.L/mol.K
M = molecular mass = 26.04 g/mol
0.910 atm × 26.04 g/mol = d × 0.0821 atm.L/mol.K×293 K
23.7 atm.g/mol = d × 24.1 atm.L/mol
d = 23.7 atm.g/mol / 24.1 atm.L/mol
d = 0.98 g/L
