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3 years ago

I need help with the table, which is speed and velocity and acceleration

Physics

2 answers:

likoan [24]3 years ago

5 0

The first box is Acceleration
the second box is Speed
the third box is Speed
the fourth box is velocity
the fifth box is Speed.

The reason the first box is acceleration is because let's say you are about to go up a hill you need to add acceleration to make it up the hill, I was going to say speed but it wouldn't said what mph was.

The reason the second, third,and fifth box is speed is because it is telling up that an object is going _mph (the blank is where you put your estimate of speed of an object).

The reason the fourth box is velocity is because velocity is both magnitude and direction so in the fourth box it says that the race car made a slight left turn which is a direction that the car is going in.

Hope this helped :)
Have a great day

tankabanditka [31]3 years ago

3 0

Acceleration ... speeding up, slowing down, or changing direction.
The roller coaster and the racecar.

Speed ... distance traveled and how much time it takes.
The cyclist and the athlete.

Velocity ... a speed AND its direction.
The geese.

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A motorcycle is following a car that is traveling at constant speed on a straight highway. Initially, the car and the motorcycle

xz_007 [3.2K]

Answer:

a) $\Delta{t} = 5.39s$

b) the motorcycle travels 155 m

Explanation:

Let $t_2-t_1 = \Delta{t}$ , then consider the equation of motion for the motorcycle (accelerated) and for the car (non accelerated):

$v_{m2}=v_0+a\Delta{t}\\x+d=(\frac{v_0+v_{m2}}{2} )\Delta{t}\\v_c = v_0 = \frac{x}{\Delta{t}}$

where:

$v_{m2}$ is the speed of the motorcycle at time 2

$v_{c}$ is the velocity of the car (constant)

$v_{0}$ is the velocity of the car and the motorcycle at time 1

d is the distance between the car and the motorcycle at time 1

x is the distance traveled by the car between time 1 and time 2

Solving the system of equations:

$\left[\begin{array}{cc}car&motorcycle\\x=v_0\Delta{t}&x+d=(\frac{v_0+v_{m2}}{2}}) \Delta{t}\end{array}\right]$

$v_0\Delta{t}=\frac{v_0+v_{m2}}{2}\Delta{t}-d \\\frac{v_0+v_{m2}}{2}\Delta{t}-v_0\Delta{t}=d\\(v_0+v_{m2})\Delta{t}-2v_0\Delta{t}=2d\\(v_0+v_0+a\Delta{t})\Delta{t}-2v_0\Delta{t}=2d\\(2v_0+a\Delta{t})\Delta{t}-2v_0\Delta{t}=2d\\a\Delta{t}^2=2d\\\Delta{t}=\sqrt{\frac{2d}{a}}=\sqrt{\frac{2*58}{4}}=\sqrt{29}=5.385s$

For the second part, we need to calculate x+d, so you can use the equation of the car to calculate x:

$x = v_0\Delta{t}= 18\sqrt{29}=96.933m\\then:\\x+d = 154.933$

3 0

3 years ago

Speakers A and B are vibrating in phase. They are directly facing each other, are 8.2 m apart, and are each playing a 78.0 Hz to

Stels [109]

Answer:6.298,4.1,1.9015

Explanation:

Wavelength= $\frac{velocity of sound }{frequency}$

= $\frac{343}{78}$ =4.397 m

Distance of 3rd speaker from speaker A is x

From B 78-x

Difference between the distances must be a whole number of wavelengths

First

$x-\left ( 8.2-x\right )=4.397$ for 1 st wavelength

2x=8.2+4.397=12.597

x=6.298m

second

For zero wavelength

$x-\left ( 8.2-x\right )=0$

2x=8.2

x=4.1m

Third

$\left ( 8.2-x\right )-x=4.397$

x=1.9015 m

6 0

2 years ago

Carbon dioxide can be represented by the chemical formula

Vitek1552 [10]

Answer:

Your answer is B co2

Explanation:

8 0

2 years ago

Read 2 more answers

Explain the relationship between speed, velocity and acceleration

Montano1993 [528]

Speed is the rate at which something covers a distance; velocity is the same but it takes into account whether it goes forwards or backwards; and acceleration is the rate of an increase in speed.

8 0

3 years ago

A reaction where the consequences of a reaction cause a succeeding like reaction is called a mass reaction .

Mumz [18]

Answer:

not 100% sure what you were asking.

Explanation:

A reaction where the consequences of a reaction cause a succeeding like reaction is called a <u>chain reaction</u>.

3 0

3 years ago