Answer:
480.40 g.
Explanation:
- According to the balanced equation:
<em>2 SO₂(g) + O₂(g) → 2 SO₃(g),</em>
it is clear that 2.0 moles of SO₂ react with 1.0 mole of oxygen to produce 2.0 moles of SO₃.
- We can get the no. of moles of SO₃ produced:
∵ 2.0 moles of SO₂ produce → 2.0 moles of SO₃, from the stichiometry.
∴ 6.0 moles of SO₂ produce → 6.0 moles of SO₃.
- Then, we can get the mass of the produced 6.0 moles of SO₃ using the relation:
<em>mass = no. of moles x molar mass of SO₃</em> = (6.0 moles)(80.066 g/mol) = <em>480.396 g ≅ 480.40 g.</em>
Answer:
The words that have some thing match them together and that’s your answer!
Explanation:
Answer:
84.30 mm Hg
Explanation:
In 100 cm³ of solution we have: 40 cm³ C6H6 and 60 cm³ CCl4. Given the densities we can calculate their masses and number of moles, and since by Raoult´s law
Ptotal = XAPºA + XBPºB
where XA= mol fraction =na/(na +nb) and PºA vapor pressure pure of pure component A
m C6H6 = 40 cm³ x 0.87865 g/cm³ = 35.146 g
mol C6H6 = 35.146 g/ 78.11 g/mol = 0.45 mol
mass CCl4 = 60 cm³ x 1.5940 g/cm³ = 95.640 g
mol CCl4 = 95.640 g / 153.82 g/mol = 0.62 mol
mol tot = 1.07
XC6H6 = 0.45/ 1.07 = 0.42 XCCl4 = 0.62/1.07 =0.58
Ptot (mmHg) = 0.42 x 74.61 + .58 x 91.32 = 84.30 mmHg
If I'm not mistaking the answer is C. Reactiviy with oxygen. Hopfully I'm correct and I hope it helps!
