Answer:
C₂ = 2.22 KJ/kg °C
Explanation:
Since, both objects are in thermal contact. Therefore, the law of conservation of energy tells us that:
where,
m₁ = mass of ice = 1 kg
C₁ = specific heat of ice = 2.04 KJ/kg.°C
ΔT₁ = Change in Temperature of Ice = -8.88°C - (-24°C) = 15.12°C
m₂ = mass of metal block = 1 kg
C₂ = specific heat of metal = ?
ΔT₂ = Change in Temperature of Metal Block = 5°C - (-8.88°C) = 13.88°C
Therefore, using these values in the equation, we get:
<u>C₂ = 2.22 KJ/kg °C</u>
Answer:
The angular velocity, clockwise
Explanation:
The mass of the man, m = 72 kg
The center of mass of the man will be at the middle of his body, particularly around his abdomen.
Height of the center of mass, h = 0.71 m
The speed of the man, v₁ = 1.35 m/s
Moment of inertia about the ankle joint, I = 66 kg/m²
Based on the principle of conservation of angular momentum (about the ankle joint):
Angular momentum before impact = Angular momentum after impact
Angular momentum before impact = -mv₁h
Angular momentum before impact = -(72 * 1.35 * 0.71)
Angular momentum before impact = -69.012 kg m²/s...............(1)
Angular momentum after impact =
Angular momentum after impact = .................(2)
The angular velocity, clockwise