In a photoelectric experiment, a metal is irradiated with light of energy 3.56 eV. If a stopping potential of 1.10 V is required , what is the work function of the metal?
1 answer:
Answer:
2.46 eV
Explanation:
It is given that,
The energy of light that fall on the metal = 3.56 eV
The stopping potential of the metal = 1.1 V
We need to find the work function of the metal. It is given by the relation as follows :
W = E-KE ...(1)
Where KE is the kinetic energy of the ejected electron and it is given by :
KE = V×e
= 1.1 eV
Put all the values in formula (1)
W = 3.56 eV - 1.1 eV
= 2.46 eV
Hence, the work function of the metal is 2.46 eV. Hence, the correct option is (c).
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Equilibrium implies that the net force on the body is 0, therefore the body undergoes no acceleration. No acceleration means the velocity doesn't change.
The body's velocity stays constant over time.
Answer:
49 m/s
Explanation:
Initial potential energy = final kinetic energy
PE = KE
mgh = ½ mv²
v = √(2gh)
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