To solve this problem it is necessary to apply the concepts related to the conservation of energy, specifically the potential elastic energy against the kinetic energy of the body.
By definition this could be described as
Where
k = Spring constant
x = Displacement
m = mass
v = Velocity
This point is basically telling us that all the energy in charge of compressing the spring is transformed into the energy that allows the 'impulse' seen in terms of body speed.
If we rearrange the equation to find v we have
Our values are given as
Replacing at our equation we have then,
Therefore he speed of the car before impact, assuming no energy is lost in the collision with the wall is 2.37m/s
A: objects that shine
Visible: Our eyes detect visible light<span>. Fireflies, </span>light<span> bulbs, and stars all </span>emit<span> visible </span>light<span>. Ultraviolet: Ultraviolet radiation is </span>emitted<span> by the Sun and are the reason skin tans and burns. "Hot" </span>objects<span> in space </span>emit<span> UV radiation as well.</span>
Answer:
Torque on the coil will be ZERO
Explanation:
As we know that the magnetic moment of the closed current carrying coil is always along its axis and it is given as
now we know that magnetic field is also along the axis of the coil so here as we know the equation of torque given as
so we have
Answer:
Part 1) Time of travel equals 61 seconds
Part 2) Maximum speed equals 39.66 m/s.
Explanation:
The final speed of the train when it completes half of it's journey is given by third equation of kinematics as
where
'v' is the final speed
'u' is initial speed
'a' is acceleration of the body
's' is the distance covered
Applying the given values we get
Now the time taken to attain the above velocity can be calculated by the first equation of kinematics as
Since the deceleration is same as acceleration hence the time to stop in the same distance shall be equal to the time taken to accelerate the first half of distance
Thus total time of journey equals
Part b)
the maximum speed is reached at the point when the train ends it's acceleration thus the maximum speed reached by the train equals 
