In a photoelectric experiment, a metal is irradiated with light of energy 3.56 eV. If a stopping potential of 1.10 V is required
, what is the work function of the metal?
a. 1
b. 3.20 eV
c. 2.46 eV
d. 0.644 eV
e. 1.83 eV
d. 4.66 eV
1 answer:
Answer:
2.46 eV
Explanation:
It is given that,
The energy of light that fall on the metal = 3.56 eV
The stopping potential of the metal = 1.1 V
We need to find the work function of the metal. It is given by the relation as follows :
W = E-KE ...(1)
Where KE is the kinetic energy of the ejected electron and it is given by :
KE = V×e
= 1.1 eV
Put all the values in formula (1)
W = 3.56 eV - 1.1 eV
= 2.46 eV
Hence, the work function of the metal is 2.46 eV. Hence, the correct option is (c).
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