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sergey [27]
3 years ago
8

What is the velocity of the rock after 3.00 seconds (the rock is falling from a cliff)

Physics
1 answer:
tankabanditka [31]3 years ago
7 0

Answer:

29.4 m/s

Explanation:

Using the formula: V=Vi + g.t

where V: final velocity, this is  what you want.

Vi: initial velocity, equals to zero as it is falling from rest.

g: acceleration due to gravity = 9.8

t: time, which equals 3 sec.

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A 25,000 kg traveling east collides with a 2,000 kg truck standing still on the tracks. After the collision the train and truck
Elis [28]

Answer:

24.084 m/s

Explanation:

From the law of conservation of linear momentum

Total momentum before collision equals to the total momentum after collision

Since momentum=mv where m is mass and v is velocity

M_{truck}V_{truck}=V_{common}*(M_{truck} +M_{standing}) where M_{truck} is the mass of the truck, V_{truck} is velocity of the truck, V_{common} is the common velocity of moving and standing truck after collision and M_{standing} is the mass of the standing truck

Making V_{truck} the subject we obtain

V_{truck}=\frac { V_{common}*(M_{truck} +M_{standing})}{M_{truck}}

Substituting M_{truck} as 25000 Kg, V_{common} as 22.3 m/s, M_{standing} as 2000 Kg we obtain

V_{truck}=\frac { 22.3 m/s *(25000 Kg +2000 Kg)}{25000}= 24.084 m/s

Therefore, assuming no friction and considering that after collision they still move eastwards hence common velocity and initial truck velocities are positive

The truck was moving at 24.084 m/s

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) what is kinetic energy, and how does it differ from potential energy?
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 Kinetic energy<span>is the </span>energy<span> of body or a system with respect to the motion of the body or of the particles in the system. </span>Potential energy<span> is the stored </span>energy<span> in an object of system because of its position or configuration.</span>
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