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enyata [817]
3 years ago
15

When casting low carbon steel under certain mold conditions, the mold constant in Chvorinov's rule = 4.0 min/cm2. Determine how

long solidification will take for a rectangular casting whose length = 30 cm, width = 15 cm, and thickness = 20 mm.
Engineering
1 answer:
Goshia [24]3 years ago
5 0

Answer:

Solidification time is 2.78 min.

Explanation:

Chvorinov's rule states that the solidification time is directly proportional to the square of ratio of total volume to the total surface area of the cast.

Step1

Given:

Chvorinov's rule constant is 4 min/cm².

Length of the rectangular cast is 30 cm.

Width of the rectangular cast is 15 cm.

Thickness of the rectangular cast is 20 mm or 2 cm.

Calculation:

Step2

Volume of the cast is calculated as follows:

V=l\times b\times t

V=30\times15\times2

V = 900 cm³.

Step3

Total surface area is calculated as follows:

A=2(lb+bt+tl)

A=2(30\times15+15\times2+2\times30)

A=1080 cm².

Step4

Time of solidification is calculated as follows:

t=K(\frac{V}{A})^{2}

t=4(\frac{900}{1080})^{2}

t = 2.78 min.

Thus, solidification time is 2.78 min.

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butalik [34]

Answer:

Exit velocity V_2=1472.2 m/s.

Explanation:

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        h_1=3624.7\frac{KJ}{Kg}

At exit:Lets take exit velocity V_2

We know that if we know only one property inside the dome  then we will find the other property by using steam property table.

Given that dryness or quality of steam at the exit of nozzle  is 0.85 and pressure P=80 bar.So from steam table we can find the other properties.

Properties of saturated steam at 80 bar

   h_f= 1316.61\frac{KJ}{Kg} ,h_g= 2757.8\frac{KJ}{Kg}

So the enthalpy of steam at the exit of turbine  

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h_2=1316.61+0.85(2757.8-1316.61)\frac{KJ}{Kg}

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Now from first law for open system

h_1+\dfrac{V_1^2}{2}+Q=h_2+\dfrac{V_2^2}{2}+w

In the case of adiabatic nozzle Q=0,W=0

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V_2=1472.2 m/s

So Exit velocity V_2=1472.2 m/s.

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W / nRT = ln (Vf / Vi)

W / nRT = 2.303 log (Vf / Vi)

W / nRT * 1 / 2.303 = log (Vf / Vi)

Vf / Vi = Antilog (W / nRT * 1 / 2.303)

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Answer:

a) v = +/- 0.323 m/s

b) x = -0.080134 m

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Explanation:

Given:

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(c) the maximum velocity.

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- Separate variables:

                           v*dv = - (0.1 + sin(x/0.8)) . dx

-Integrate from v = 1 m/s @ x = 0:

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- Hence,

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                            v = sqrt (0.504)

                            v = +/- 1.004 m/s

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3 years ago
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