Answer:
The value is the temperature of the air inside the tire
340.54 K
% of the original mass of air in the tire should be released 99.706 %
Explanation:
Initial gauge pressure = 2.7 atm
Absolute pressure at inlet
= 2.7 + 1 = 3.7 atm
Absolute pressure at outlet
= 3.2 + 1 = 4.2 atm
Temperature at inlet
= 300 K
(a) Volume of the system is constant so pressure is directly proportional to the temperature.


340.54 K
This is the value is the temperature of the air inside the tire
(b). Since volume of the tyre is constant & pressure reaches the original value.
From ideal gas equation P V = m R T
Since P , V & R is constant. So
m T = constant




value of the original mass of air in the tire should be released is

⇒ -0.99706
% of the original mass of air in the tire should be released 99.706 %.
These organelles are like the organs in a human and they help the cell stay alive. Each organelle has it's own specific function to help the cell survive. The nucleus of a eukaryotic cell directs the cell's activities and stores DNA. Eukaryotes also have a golgi apparatus that packages and distributes proteins.
<span>The standard DH for this reaction is -852 kJ/rxn. When attacking a problem like this, the first thing to always do is to convert grams (which is a unit of measurement) into moles (which is a unit of chemistry). The atomic weight of aluminum is 26.98 g/mol, so you can divide your mass by the molecular weight to find that you have 1.81 mol of aluminum. Note then that you use up two moles of aluminum per reaction cycle (as defined by the coefficient), so you can divide your number of moles of aluminum by 2 mol Al/rxn. So now you know that you have enough aluminum for .903 reaction cycles, so you can multiply your standard enthalpy by the number of reaction cycles that can progress, and you should end up with a total of -769 kJ of energy, which equates to a release or evolution (rather than an absorption) of 769 kJ of energy.</span>
3.51 × 10^-7m
Explanation:
Refractive index = wavelength of the light in air ÷ wavelength in the medium
wavelength in the medium = wavelength of the light in air ÷ refractive index
= 5.4 * 10^-7 ÷ 1.54
= 3.51 × 10^-7m