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Natalija [7]
3 years ago
14

An element has a half-life of 5.0 days. How many days would

Chemistry
1 answer:
Olin [163]3 years ago
3 0

Answer:

15 days

Explanation:

Given half-life = 5 days => k = 0.693/half-life = 0.693/5 days⁻¹

A = A₀e^-k·t => t = ln(A/A₀) / -k = ln(1/8) / -0.1386 days⁻¹ =  15 days

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10. Air is a homogenous mixture of gases. Oxygen is 20% by volume of air typically. What
raketka [301]

Answer:

893 moles

Explanation:

An ideal gas at STP occupies 22.4 liters. Calculating Oxygen as if it were an ideal gas there are . 893 moles of Oxygen in 20.0 liters.

3 0
3 years ago
The amount of kinetic energy an object has depends on which feature of the object?
maks197457 [2]

Answer:

mass

Explanation:

The amount of kinetic energy an object has, depends on its mass and its speed.

5 0
3 years ago
Give an example of how today’s forensic chemists can help solve crimes
goldenfox [79]

they can find dna at the crime scene wich will lead them to the guilty party

4 0
3 years ago
The momentum of an object depends on which two quantities?
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3 years ago
Read 2 more answers
A soluble iodide was dissolved in water. Then an excess of silver nitrate, AgNO3, was added to precipitate all of the io- dide i
Sergeeva-Olga [200]

Answer:

m_{I^-}=1.18gI^-

Explanation:

Hello,

In this case, the reaction is given as:

I^-+AgNO_3\rightarrow AgI+NO_3^-

Thus, starting by the yielded grams of silver iodide, we obtain:

n_{I^-}=2.185gAgI*\frac{1molAgI}{234.77gAgI}*\frac{1molI}{1molAgI}=9.31x10^{-3}molI^-

Which correspond to the iodide grams in the silver iodide. In such a way, by means of the law of the conservation of mass, it is known that the grams of each atom MUST remain constant before and after the chemical reaction whereas the moles do not, therefore, the mass of iodine from the silver iodide will equal the mass of iodine present in the soluble iodide, thereby:

m_{I^-}=9.31x10^{-3}molI^-\frac{127gI^-}{1molI^-} =1.18gI^-

And the rest, correspond to the iodide's metallic cation which is unknown. Such value has sense since it is lower than the initial mass of the soluble iodide which is 1.454g, so 0.272 grams correspond to the unknown cation.

Best regards.

7 0
4 years ago
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