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UkoKoshka [18]
3 years ago
15

What is the pH of 0.12M HNO3

Chemistry
1 answer:
Phoenix [80]3 years ago
4 0

Answer:

pH= 0.92

Explanation:

HNO3-> H^+ +NO3^-

HNO3 is a strong acid, so it fully dissociates

[HNO3] = 0.12M    [H^+] = 0.12M  

pH= -log[H^+]

pH=-log[.12] = 0.92

pH = 0.92

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Given a sample of poly[ethylene-stat-(vinyl acetate)] A.Calculate the mean repeat unit molar mass for a sample of poly[ethylene-
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Answer:

a) The mean repeat unit molar mass for PEVA is 30.72 g/mol

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Explanation:

Given that;

the wt% of copolymer consist of 12.9 wt% of vinyl acetate and 87.1 wt% Ethylene.

Basis: 100 g of PEVA consist of 12.9 of vinyl acetate and 87.1g of Ethylene.

now we calculate the mole fraction of vinyl acetate Ethylene in the copolymer;

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so

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Total moles = 0.1498 mol + 3.1052 mol = 3.255 mol

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mole percent of vinyl acetate X_{V} = moles of vinyl acetate / total  moles

X_{V} = (0.1498 mol / 3.255 mol) × 100

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mole percent of Ethylene X_{E} = moles of Ethylene / total  moles

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X_{E}  = 95.397% ≈ 95.4%

we know that, mean repeat unit molar mass for a sample = ∑X_{i}M_{i}

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so or the PEVA

mean repeat unit molar mass M = ( X_{V}M_{V}) + ( X_{E}M_{E})

so we substitute

M = ( 4.6% × 86.09) + ( 95.4% × 28.05 )

M = 3.96014 + 26.7597

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Therefore, The mean repeat unit molar mass for PEVA is 30.72 g/mol

b)

Degree of polymerization

DP_{n} = \frac{M_{n} }{M}

where M_{n} is the number average molecular weight ( 39,870 g/mol )

so we substitute

DP_{n} = 39,870 g/mol / 30.72 g/mol

DP_{n}  = 1297.85 ≈ 1300   { 3 significance figure }

Therefore, degree of polymerization of the copolymer is 1300

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