Answer:
Ba: 1s² 2s²2p⁶ 3s²3p⁶ 4s²3d¹⁰4p⁶ 5s²4d¹⁰5p⁶ 6s²
Step-by-step explanation:
Step 1. Locate barium in the Periodic Table.
It's in Period 6, Group 2: Element 56 (highlighted blue in the Periodic Table below).
Step 2. Add 54 electrons to the energy levels
You add then in the order shown in the diagram below.
The complete electron configuration is:
Ba: 1s² 2s²2p⁶ 3s²3p⁶ 4s²3d¹⁰4p⁶ 5s²4d¹⁰5p⁶ 6s²
n = 2 + 8 + 8 + 18 + 18 + 2 = 56
Answer:
No, it is not feasible because the Gibbs free energy change is positive
Explanation:
∆Hreaction= (-602 KJ/mol) - (-348 KJ/mol) = -254 KJ/mol
∆Sreaction = (42 + 27) J/Kmol - (33 + 44) J/K = -8J/Kmol
From;
∆G = ∆H - T∆S
∆G = 254 × 10^3 J/mol - [340K × (-8 J/Kmol)]
∆G = 2.57 × 10^5 J/mol
Note that when the change in free energy is positive, a reaction is non spontaneous. Only a reaction that has a negative change in free energy is spontaneous.
B. 3.77 L is the new volume occupied by the gas.
<u>Explanation:</u>
As per Avogadro's law, which states that if the pressure and temperature held constant, then an equal volume of the gases will occupy an equal number of molecules. It can be written as,

Here, V1, volume of the helium gas = 2.9 L
V2, volume of the additional helium gas in the balloon = ?
n1, moles of helium gas = 0.150 mol
n2, number of moles of additional helium gas = 0.150 + 0.0450 = 0.195 mol
We have to rearrange the equation for V2 as,
V2 = 
Now Plugin the values as,
V2 = 
= 3.77 L
So the new volume of the balloon is 3.77 L.
Answer: d) 16.34 grams
Explanation:
To calculate the moles :

According to stoichiometry :
As 2 moles of
are produced by= 4 moles of 
Thus 0.292 moles of
are produced by= =
of 
Mass of 
Thus 16.34 g of
will be needed
Answer:
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