Sound is produced when something <span>vibrates.
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Answer:
The intensity at a spot 71 m away is 
Explanation:
Given:
Initial intensity,
at a distance, 
Required:
New intensity,
at a distance, 
Using the inverse square law,
I ∝ 
⇒

×

Thus, the intensity at a spot that is 71 m away is 
Answer:
Weight needed to balance the bar is 
Explanation:
Given the weight of the bar is 
The length of the bar is 
The weight of the bar will be uniformly distributed over the entire span. We will consider this as a point load acting in the middle of span length, which is at a distance of
from both ends.
Now applying momentum equation about balanced load we get, (see attachment)

Answer:
d = 20.25 m
Explanation:
h = 6m, V = 14 m/s, θ=14°
⇒ Vx=V × Cosθ=13.58 m/s and Vy = V × Sinθ=3.39 m/s
to find time t by h=-Vy t + 1/2 g t² (after putting value and simplifying) (-ve for downward motion)
4.9 t² - 3.39 t - 6 =0
⇒ t=1.5 sec (ignoring -ve root)
Now Vx = d/t
13.5 m/s = d / 1.5 s ⇒ d = 20.25 m
Accourding to newtons second law of motion:
Force = mass * acceleration
F = ma
a = F/m