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Lady_Fox [76]
4 years ago
13

A 140

Physics
1 answer:
Doss [256]4 years ago
7 0
There is not enough information given tl be able to solve this problem
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A 68.0-kg person jumps from rest off a 2.20-m-high tower straight down into the water. Neglect air resistance during the descent
Margarita [4]

Answer:

F= 1333.767\,N

Explanation:

The velocity of the swimmer just before touching the water is:

v = -\sqrt{2\cdot (9.807\,\frac{m}{s^{2}} )\cdot (2.20\,m)}

v \approx 6.569\,\frac{m}{s}

The average force exerted on the diver by the water is determined by the use of the Principle of Energy Conservation and the Work-Energy Theorem:

(68\,kg)\cdot (9.807\,\frac{m}{s^{2}})\cdot (2.20\,m) +\frac{1}{2}\cdot (68\,kg)\cdot (6.569\,\frac{m}{s} )^{2}-F\cdot(2.20\,m) = 0\,J

F= 1333.767\,N

6 0
3 years ago
Read 2 more answers
A 1.1 kg ball is attached to a ceiling by a 2.16 m long string. The height of the room is 5.97 m . The acceleration of gravity i
nydimaria [60]

1. -23.2 J

The gravitational potential energy of the ball is given by

U=mgh

where

m = 1.1 kg is the mass of the ball

g = 9.8 m/s^2 is the acceleration of gravity

h is the height of the ball, relative to the reference point chosen

In this part of the problem, the reference point is the ceiling. So, the ball is located 2.16 m below the ceiling: therefore, the heigth is

h = -2.16 m

And the gravitational potential energy is

U=(1.1 kg)(9.8 m/s^2)(-2.16 m)=-23.2 J

2. 41.1 J

Again, the gravitational potential energy of the ball is given by

U=mgh

In this part of the problem, the reference point is the floor.

The height of the ball relative to the floor is equal to the height of the floor minus the length of the string:

h = 5.97 m - 2.16 m = 3.81 m

And so the gravitational potential energy of the ball relative to the floor is

U=(1.1 kg)(9.8 m/s^2)(3.81 m)=41.1 J

3. 0 J

As before, the gravitational potential energy of the ball is given by

U=mgh

Here the reference point is a point at the same elevation of the ball.

This means that the heigth of the ball relative to that point is zero:

h = 0 m

And so the gravitational potential energy is

U=(1.1 kg)(9.8 m/s^2)(0 m)=0 J

4 0
4 years ago
g is incident on 3 successive sheets of polarizing material. The transmission axis of the first sheet is vertical. The transmiss
murzikaleks [220]

Answer:

The intensity of light passing from the third polarizer is 3Io/16.

Explanation:

The law of Malus is given by

I=I_o cos^2\theta

Let the incident intensity of light is Io.

The intensity of light passing from the first polarizer is

I' = \frac{I_o}{2}

The intensity of light passing from the second polarizer is

I''=\frac{I_o}{2}\times cos^230 =\frac{3I_o}{8}

The intensity of light passing from the third polarizer is

I''' = \frac{3I_o}{8}\times cos^2 60\\\\\\I''' = \frac{3I_o}{16}

6 0
3 years ago
PLEASE HELP ILL GIVE CROWN!!!!!!!!!!!!!!!
kkurt [141]

Explanation:

can i get the crown please now hehehh ahhhahah hoohoh

they have a pictures just click and thats the answer ↑

8 0
3 years ago
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Random pictures<br><br><br> Bloop blah bloop bleep
Dvinal [7]

Answer:

Yesssss its 1235 and you are beautiful

7 0
3 years ago
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