First, we write the equation of formation of potassium chloride from chlorine:
2K + Cl₂ → 2KCl
Each mole of Cl₂ produces two moles of KCl
Therefore, the conversion factor is:
Moles of chlorine = 2 x moles of potassium chloride
Answer:
38.3 miles
Explanation:
First, we <u>convert 1.95 gallons to mililiters</u>:
- 1.95 gallons * = 7380.75 mL
Then we <u>calculate how many grams of octane are available for the reaction</u>, using its density:
- 0.6916 g/mL * 7380.75 mL = 5104.53 g C₈H₁₈
Now we <u>convert octane grams into octane moles</u>, using its molar mass:
- 5104.53 g C₈H₁₈ ÷ 114 g/mol = 44.78 mol C₈H₁₈
Then we <u>calculate how many kJ are produced from the combustion of 44.78 mol C₈H₁₈</u>, <em>if 2 moles produce 10900 kJ</em>:
- 44.78 mol * 10900 kJ / 2 mol = 244032 kJ
We<u> calculate how many seconds is the car available to keep going</u>, <em>if it spends 115 kJ per second</em>:
- 244032 kJ * 1 s / 115 kJ = 2122.02 s
We convert seconds to hours:
- 2122.02 / 3600 = 0.59 hours
Finally we calculate the distance:
- 65 mi/hour * 0.59 hour = 38.3 mi
Answer:
The answer is Hg.
Explanation:
Symbol for Mercury is Hg.
Answer:
58425.84 kJ is released when 4.337 pounds of liquid ethanol are burned.
Explanation:
Given that:-
When 1 gram of liquid ethanol is burnt, 29.7 kJ of energy is released.
The conversion of pounds to gram is shown below as:-
1 pound = 453.6 gram
Given mass of liquid ethanol = 4.337 pounds.
So,
4.337 pounds = 453.6*4.337 grams = 1967.2 grams
Thus,
When 1967.2 gram of liquid ethanol is burnt, 29.7*1967.2 kJ of energy is released.
<u>58425.84 kJ is released when 4.337 pounds of liquid ethanol are burned.</u>
Can’t tell ya bc you didn’t list the answers