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Usimov [2.4K]
3 years ago
10

What is the equation that illustrates the relationship between wave velocity, frequency, and wavelength?

Chemistry
2 answers:
victus00 [196]3 years ago
7 0

Answer:

Explanation:

Speed of wave is the distance cover by the wav in a given period of time.

The relation of wave speed with frequency and wavelength is given below,

Formula:

Speed of light = wavelength × frequency

Frequency and wavelength of lights are inversely proportional to each other.

The wave of light having highest frequency have shortest wavelength and the light with the shortest frequency having highest wavelength.

c = λ × f

λ = c/f

This formula shows that both are inversely related to each other.

The speed of light is 3×10⁸ m/s

Frequency is taken in Hz.

It is the number of oscillations, wave of light make in one second.

Wavelength is designated as "λ" and it is the measured in meter. It is the distance between the two crust of two trough.

lina2011 [118]3 years ago
3 0

*view screenshot/image for answer & explanation*

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70 POINTS What type of organic compound contains the following functional group?
andrew-mc [135]

The compound contains an ester functional group.

An ester is a carbonyl (C=O) group with an alkyl (R) group on one side and an alkoxy (OR) group on the other.

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8 0
4 years ago
AL2O3 and ZNO are which oxides​
Nesterboy [21]

Answer:

<em><u>Metal oxides</u></em>

Explanation:

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6 0
4 years ago
A 100.0 mL solution containing 0.923 gof maleic acid (MW=116.072 g/mol) is titrated with 0.265 M KOH. Calculate the pH of the so
Vlad1618 [11]

Answer:

pH = 9,57

[M²⁻] = 7,948x10⁻²M

[HM⁻] = 4x10⁻⁵M

[H₂M] = 0M

Explanation:

The moles of maleic acid presents in the solution are:

0,923g×\frac{1mol}{116,072g}=7,952x10⁻³moles of H₂M

60,0mL of 0,265M KOH are:

0,0600L×\frac{0,265mol}{1L}=0,0159 moles of KOH

The reactions of maleic acid (H₂M) and then with HM⁻ are:

H₂M + KOH → HM⁻ + H₂O + K⁺ (1)

HM⁻ + KOH → M²⁻ + H₂O + K⁺ (2)

For a complete transformation of H₂M in HM⁻ there are necessaries 7,952x10⁻³moles of KOH. As the moles of KOH are 0,0159 moles, the restant moles are:

0,0159 - 7,952x10⁻³ = <em>7,948x10⁻³ moles of KOH</em>

By (2), the moles produced of M²⁻ are the same as moles of KOH, <em>7,948x10⁻³  moles, </em>and moles of HM⁻ are:

7,952x10⁻³ -<em> </em>7,948x10⁻³ <em> = 4x10⁻⁶ moles of HM⁻</em>

Using Henderson-Hasselbalch formula:

pH = pka + log₁₀ [M²⁻] /[HM⁻]

pH = 6,27 + log₁₀ <em>7,948x10⁻³ / 4x10⁻⁶</em>

pH = 9,57

The moles of M²⁻ are 7,948x10⁻³  and volume of the solution is 0,1000L,

[M²⁻] = 7,948x10⁻²M

Moles of HM⁻ are 4x10⁻⁶:

[HM⁻] = 4x10⁻⁵M

And there is not H₂M:

[H₂M] = 0M

I hope it helps!

8 0
3 years ago
I will mark brainliest if you are correct
alexgriva [62]

Answer:

The right answer to this is (b)

3 0
3 years ago
Read 2 more answers
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