How many grams of MnCl2 need to be added to 5 liters of water to make a 0.25 M solution?
1 answer:
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Answer:
The answer to your question is 33.4 ml
Explanation:
Data
volume 1 = V1 = 42 ml
temperature 1 = T1 = 20°C
temperature 2 = T2 = -60°C
Volume 2 = V2 = x
Process
1.- Convert celsius to kelvin
T1 = 20 + 273 = 293°K
T2 = -60 + 273 = 233°K
2.- Use the Charles' law to solve this problem
Solve for V2
V2 =
3.- Substitution
V2 =
4.- Simplification
V2 =
5.- Result
V2 = 33.4ml