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Anna007 [38]
3 years ago
5

Which of the following compounds represents a covalent bond?

Chemistry
1 answer:
Assoli18 [71]3 years ago
8 0
Bis the correct answer
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In 2011, a computer named Watson competed against two humans on a popular television quiz show and won. Watson listened to each
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A computer is made up of wires which is like nerves in our body they send signals throughout our bodies and tell us what to do about a situation. The hard drive of a computer is just like our brain which is the main component of the nervous system it controls involuntary, voluntary, movement and coordination. Also, just like the keys and mouse of a computer we have sensory neurons which pick up what is around us by touch.

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Determine the concentration of nh3(aq) that is required to dissolve 743 mg of agcl(s) in 100.0 ml of solution. the ksp of agcl i
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Answer:

1.1 M

Explanation:

The dissociation of AgCl_{(s)} is as follows:

AgCl \leftrightharpoons Ag^+_{(aq)}+Cl^-_{(aq)}

Given Value for K_{sp} = 1.77*10^{-10}

The equation for the reaction for the formation of complex ion Ag(NH_3)^+_2 is :

Ag^+_{(aq)}    +     2NH_3_{(aq)} \rightleftharpoons Ag(NH_3)_2^+_{(aq)}

The value of K_f = 1.6*10^7

If we combine both equation and find the overall equilibrium constant will be:

AgCl \leftrightharpoons Ag^+_{(aq)}+Cl^-_{(aq)}

Ag^+_{(aq)}    +     2NH_3_{(aq)} \rightleftharpoons Ag(NH_3)_2^+_{(aq)}

<u>                                                                                                      </u>

AgCl_{(s)}+2NH_3_{(aq)} \rightleftharpoons Ag(NH_3)_2^+_{(aq)} + Cl^-_{(aq)}

                                 K = (1.77*10^{-10})(1.6*10^7)

                                  K = 0.00283

If [NH_3] = x M

The solubility of  AgCl_{(s)} in the NH_3 solution will be:

x = 743*10^{-3}g * \frac{mol AgCl}{143.32g}*\frac{1}{0.1000L}

x = 0.0518 M

Constructing an ICE Table; we have :

                             AgCl_{(s)} + 2 NH_3{(aq)} \rightleftharpoons Ag(NH_3)_2^+_{(aq)} + Cl^-_{(aq)}

Initial  (M)                                     x                   0                      0

Change  (M)                       -2 (0.0518)      + 0.0518          + 0.0518

Equilibrium (M)                    x - 0.1156          0.0518             0.0518

Equilibrium constant;

(K) = \frac{[Ag(NH_3)_2^+][Cl^-]}{[NH_3]^2}

0.00283 = \frac{(0.0518)^2}{(x-0.1156)^2}

0.00283 = (\frac{0.0518}{x-0.1156})^2

x = 0.1156 + \sqrt{\frac{0.0518^2}{0.00283} }

x = [NH₃] =  1.089 M

[NH₃] ≅ 1.1 M                

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3 years ago
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Answer: Can i see the question

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Draw the major organic product of the regioselective reaction of 2-methyl-2-pentene with H2O in presence of H2SO4. You do not ha
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Answer:

2-methyl-2-pentanol is produced as a major product

Explanation:

  • Double bond in 2-methyl-2-pentene is protonated first by consuming a proton from H_{2}SO_{4}.
  • A carbocation intermediate is formed after protonation of double bond. Most stable carbocation is formed as a major intermediate.
  • Here a tertiary carbocation is formed as a major intermediate.
  • H_{2}O gives subsequent nucleophilic addition to the carbocation intermediate and produce 2-methyl-2-pentanol as a major product.
  • Reaction mechanism and major organic product has been shown below.

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4 years ago
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