When Na2O is mixed with Mn(NO3)4 it forms NaNO3 and MnO2. We start with 25.0 g

Hunter-Best [27]

Answer:

28.23 g NH₃

Explanation:

The balanced chemical equation is:

N₂(g) + 3 H₂(g) → 2 NH₃(g)

Thus, 1 mol of N₂ reacts with 2 moles of H₂ to produce 2 moles of NH₃. We convert the moles to mass (in grams) by using the molecular weight (MW) of each compound:

MW(N₂) = 2 x 14 g/mol = 28 g/mol

mass N₂= 1 mol x 28 g/mol = 28 g

MW(H₂) = 2 x 1 g/mol = 2 g/mol

mass H₂ = 3 mol x 2 g/mol = 6 g

MW(NH₃) = 14 g/mol + (3 x 1 g/mol) = 17 g/mol

mass NH₃= 2 moles x 17 g/mol = 34 g

Now, we have to figure out which is the limiting reactant. For this, we know that the stoichiometric ratio is 28 g N₂/6 g H₂. If we have 36.85 g of H₂, we need the following mass of N₂:

36.85 g H₂ x 28 g N₂/6 g H₂ = 171.97 g N₂

We have 23.15 g N₂ and we need 171.97 g. So, we have lesser N₂ than we need. Thus, the limiting reactant is N₂.

Now, we calculate the product (NH₃) by using the stoichiometric ratio 34 g NH₃/28 g N₂, with the mass of N₂ we have:

23.25 g N₂ x 34 g NH₃/28 g N₂ = 28.23 g NH₃

Therefore, the maximum amount of NH₃ that can be produced is 28.23 grams.

5 0

3 years ago

A liquid sample, with a density of .0915 g/mL has a mass of 17.7 grams.

Arlecino [84]

The relation between density, mass and volume is

$Density = \frac{Mass}{Volume}$

1) to calculate = volume

given:

Density = 0.0915 g/ mL

mass = 17.7 grams

formula used:

$Density = \frac{Mass}{Volume}$

Thus

Volume $Volume = \frac{Mass}{Density} = \frac{17.7 g}{0.915 \frac{g}{mL} } = 193.44 mL$

Answer: 193.44 mL

2) the mass of sample will be

$mass = density X volume = 0.0915\frac{g}{mL} X 76.5 mL = 6.99 = 7 g$

Answer: 7 g

5 0

3 years ago

An ideal gas is kept in a 10-liter [L] container at a pressure of 2.5 atmospheres [atm] and a temperature of 310 kelvin [K].

Hatshy [7]

Answer:

5 L.

Explanation:

From the question given above, the following data were obtained:

Initial volume (V1) = 10 L

Initial pressure (P1) = 2.5 atm

Final pressure (P2) = 5 atm

Final volume (V2) =.?

Since the temperature is constant, we shall apply the Boyle's law equation to determine the new volume of the gas. This can be obtained as follow:

P1V1 = P2V2

2.5 × 10 = 5 × V2

25 = 5 × V2

Divide both side by 5

V2 =25/5

V2 = 5 L

Thus, the new volume of the gas is 5 L

8 0

3 years ago

P−aminobenzenesulfonic acid (sulfanilic acid) is normally written in the form shown but its zwitterionic form is more stable. wr

polet [3.4K]

Zwitterion is an ion consists of equal positive and negative charges on the same molecule which make it more stable and has high melting point
p-aminobenzene sulfonic acid contains both acidic (-SO₃H) and basic groups (NH₂), the acidic group will lose one proton to give (-SO₃⁻) and the basic group will gain this proton to give (-NH₃⁺)
The structure is:

3 0

3 years ago

ANSWER FAST, EASY POINTS

abruzzese [7]

Answer:

Water molecules pull the sodium and chloride ions apart, breaking the ionic bond that held them together. After the salt compounds are pulled apart, the sodium and chloride atoms are surrounded by water molecules, as this diagram shows. Once this happens, the salt is dissolved, resulting in a homogeneous solution.

4 0

3 years ago

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