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Solnce55 [7]
3 years ago
14

A ________________ uses chemical formulas to model what happens in a chemical reaction.

Chemistry
1 answer:
notka56 [123]3 years ago
7 0

Answer:

Explanation:

Chemical equation

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DECOMPOSERS would get their energy directly from...
4vir4ik [10]
The answer is the sun
7 0
4 years ago
What happens when you put on deodorant? does it absorb heat and give off thermal energy
Lunna [17]
It absorbs heat and give off thermal energy just saying i think its right
3 0
4 years ago
If 10.0 L of oxygen gas at STP are heated to 512 Celsius what will be the new volume of the gas if the pressure is also increase
uysha [10]

Answer:

16.4 L

Explanation:

we can use the combined gas law equation that gives the relationship among volume, temperature and pressure conditions of gases.

P1V1/T1 = P2V2/T2

STP conditions are standard temperature and pressure conditions

P1 is standard pressure = 1 atm , T1 is standard temperature = 273 K

and V1 is the volume

P2 is pressure, T2 is temperature and V2 is volume at the second instance

temperature is in kelvin scale,

512 ° + 273 = 785 K

substituting the values in the equation

1 atm x 10.0 L / 273 K = 1.75 atm x V / 785 K

V = 16.4 L

new volume is 16.4 L

7 0
3 years ago
Which of these is correct regarding Thomson's cathode ray observations
uysha [10]

Answer:

c

Explanation:

8 0
3 years ago
Na-23 has 12 neutrons. What is it’s atomic number?
quester [9]

Answer:

11

Explanation:

Data obtained from the question include:

Mass number = 23

Neutron = 12

Atomic number =.?

Next, we shall determine the number of protons present in the element.

This can be achieved by doing the following:

Mass number = Proton + Neutron

Mass number = 23

Neutron = 12

Proton =...?

Mass number = Proton + Neutron

23 = Proton + 12

Collect like terms

Proton = 23 – 12

Proton = 11

The atomic number of an element is equal to the proton number.

Atomic number = proton number

Proton number = 11

Atomic number = proton = 11

Therefore, the atomic number is 11.

5 0
3 years ago
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