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svp [43]
3 years ago
11

JJ thomson experiment the atomic theory?

Chemistry
1 answer:
olga nikolaevna [1]3 years ago
3 0
Cathode Ray experiment to figure out electrons exist -> atoms can be broken up into subatomic particles
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What volume of 1.10 M SrCl2 is needed to prepare 525 mL of 5.00 mM SrCl2?
grigory [225]

Answer:- 2.39 mL are required.

Solution:- It's a dilution problem and to solve this type of problems we use the dilution equation:

M_1V_1=M_2V_2

Where, M_1 and M_2 are molarities of concentrated and diluted solutions and V_1 and V_2 are their respective volumes.

M_1 = 1.10M

M_2 = 5.00mM = 0.005M    (since, mM stands for milli molar and M stands for molar. 1M = 1000mM)

V_1 = ?

V_2 = 525 mL

Let's plug in the given values in the formula:

1.10M(V_1)=0.005M(525mL)

V_1=(\frac{0.005M*525mL}{1.10M})

V_1=2.39mL

So, 2.39 mL of 1.10M are needed to make 525 mL of 5.00mM solution.

7 0
3 years ago
Can someone answer question 3 ASAP please
allsm [11]

Answer:

Molecules must collide with sufficient energy, known as the activation energy, so that chemical bonds can break. Molecules must collide with the proper orientation. A collision that meets these two criteria, and that results in a chemical reaction, is known as a successful collision or an effective collision.

5 0
3 years ago
What is the correct name for the ionic compound Ca2P5
maks197457 [2]

Answer:

It is calcium phosphide.

Explanation:

Calcium phosphide is a salt like material that is composed of calcium and phosphorus in the ratio of 2:5. It has the appearance of red brown Crystalline salt.

It is use as rodenticide to kill rats.

It is also use in fire works.

7 0
3 years ago
Read 2 more answers
Which one of the following is not equal to 100 meters
Katena32 [7]
Where is the link can’t do any work without it
7 0
3 years ago
Titanium has five common isotopes: 46Ti (8.0%), 47Ti (7.8%), 48Ti (73.4%), 49Ti (5.5%), 50Ti (5.3%). What is the average atomic
NNADVOKAT [17]

Hey there!:

Isotopes :                          abundance :

46 Ti                                       8.0%

47 Ti                                        7.8 %

48 Ti                                      73.4 %

49 Ti                                       5.5 %

50 Ti                                         5.3 %

Weighted average =   ∑ Wa * % / 100

Therefore:

( 46 * 8.0) + (47 * 7.8 ) + (48 * 73.4 ) + ( 49 * 5.5 ) + ( 50*5.3 ) / 100 =

4792.3 / 100

= 47.923 a.m.u


       Hope that helps!

7 0
3 years ago
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