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3 years ago

Mrs. Pham has 8 apples. She wants to give 3/4 of the

Engineering

2 answers:

Sergio039 [100]3 years ago

6 0

The answer would be 32/3 or if you want the simplified version it’s 10 2/3.

irakobra [83]3 years ago

6 0

6

2 = 1/4
4 = 2/4
6= 3/4
8=4/4

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How much thermal energy is needed to raise the temperature of 15kg gold from 45⁰ C up to 80⁰ C

Levart [38]

Answer:

68.25 kJ

Explanation:

The thermal energy Q required to raise the temperature of 15kg gold from 45⁰ C up to 80⁰ C is Q = mcΔθ where m = mass of gold = 15 kg, c = specific heat capacity of gold = 130 J/kg°C and Δθ = temperature change = θ₂ - θ₁ where θ₁ = 45 °C and θ₂ = 80 °C

So, Q = mcΔθ = mc(θ₂ - θ₁)

= 15 kg × 130 J/kg°C × (80 °C - 45 °C)

= 1950 J/°C × 35 °C

= 68,250 J

= 68.25 kJ

6 0

3 years ago

In water and wastewater treatment processes a filtration device may be used to remove water from the sludge formed by a precipit

PtichkaEL [24]

Answer:

The volume of sludge after filtration is 0.914 m

Explanation:

Solution

Given that:

We have to find the Volume of sludge after filtration

Now,

The Sludge concentration is = 32%,

The sludge volume = 100 m,

The sludge concentration after filtration = 35%

Then,

The mass balance equation is stated below

Cin∀in = Cout∀out

Now,

We Solve for ∀out

∀out =Cin∀in/Cout

By substituting the values

∀out = (0.32)(100 m)/(0.35) = 0.914 m

6 0

3 years ago

Remy noticed that after oiling his skateboard wheels, it was easier to reach the speeds he needed to perform tricks. How did the

Sidana [21]

Answer:

The oil reduced friction between the moving parts of the skateboard. ( A )

Explanation:

The oil reduced Friction between the moving parts of the skateboard and this is because the reduction in friction between moving parts causes an increase in speed.

Remy will oil the moving parts that connects the wheels of the skateboard to the Board, because this is where the most friction is found. the friction between the wheels and the ground cannot be affected by oiling the wheels

4 0

3 years ago

An experimental arrangement for measuring the thermal conductivity of solid materials involves the use of two long rods that are

Kamila [148]

Answer:

Explanation:

Given:

The two rods could be approximated as a fins of infinite length.

TA = 75 0C θA = (TA - T∞) = 75 - 25 = 50 0C

TB = 55 0C θB = (TB - T∞) = 55 - 25 = 30 0C

Tb = 100 0C θb = (Tb - T∞) = (100 - 25) = 75 0C

KA = 200 W/m · K

T∞ = 25 0C

Solution:

The temperature distribution for the infinite fins are given by

θ/θb=e⁻mx

θA/θb= e-√(hp/A.kA) x1 ....................(1)

θB/θb = e-√(hp/A.kB) x1.......................(2)

Taking natural log on both sides we get,

Ln(θA/θb) = -√(hp/A.kA) x1 ...................(3)

Ln(θB/θb) = -√(hp/A.kB) x1 .....................(4)

Dicving (3) and (4) we get

[ Ln(θA/θb) /Ln(θB/θb)] = √(KB/KA)

[ Ln(50/75) /Ln(30/75)] = √(KB/200)

4 0

3 years ago

The emissivity of galvanized steel sheet, a common roofing material, is ε = 0.13 at temperatures around 300 K, while its absorpt

Step2247 [10]

Answer:

759.99W/m²

Explanation:

Question: If the temperature of the sheet is 77C,what is the incident solar radiation on aday with Tinf= Tsurr= 16°C?

Given

Energy Equation of the Gas

αs * Gs * A + h * A * (T inf - Tg) + εσA (Tsurr⁴- Tg⁴) = 0

Where σ= 5.67 *10^-8 W/m²K⁴ (Stefan-Boltzmann constant)

ε = 0.13 (Emisivity)

αs = 0.65 (Absorptivity for solar radiation)

h = 7W/m²K⁴

Tg = 77 + 273.15K = 350.15K

T inf = 16 + 273.15 = 288.15K

T surr= T inf = 288.15

Substitute the above values in the Gas Equation, we have

0.65 * Gs * A + 7 * A * (288.15 - 350.15) + 0.13 * 5.67 * 10^-8 * A * (288.15⁴ - 350.15⁴) = 0

0.65 * Gs * A = - 7 * A * (288.15 - 350.15) - 0.13 * 5.67 * 10^-8 * A * (288.15⁴ - 350.15⁴)

A cancels out, so we are left with

0.65 * Gs = - 7 * (288.15 - 350.15) - 0.13 * 5.67 * 10^-8 * (288.15⁴ - 350.15⁴)

0.65Gs = 434 - 0.7372 * 10^-8(−8,137,940,481.697)

0.65Gs = 434 + 0.7372 * 81.37940481697

0.65Gs = 493.992897231070284

Gs = 493.992897231070284/0.65

Gs = 759.9890726631850

Gs = 759.99W/m² ------- Approximated

3 0

3 years ago