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3 years ago

21 POINTS TO WHO EVER CAN ANSWER THIS

Chemistry

2 answers:

Tema [17]3 years ago

8 0

It’s considered the “universal solvent” because water dissolves more substances than any other chemical.

Furkat [3]3 years ago

6 0

Answer:

Explanation:

Water is capable of dissolving a variety of different substances, which is why it is such a good solvent. And, water is called the "universal solvent" because it dissolves more substances than any other liquid. This allows the water molecule to become attracted to many other different types of molecules.

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How many grams of O2 are present in 44.1 L of O2 at STP?

ycow [4]

Taking into accoun the STP conditions and the ideal gas law, the correct answer is option e. 63 grams of O₂ are present in 44.1 L of O2 at STP.

First of all, the STP conditions refer to the standard temperature and pressure, where the values used are: pressure at 1 atmosphere and temperature at 0°C. These values are reference values for gases.

On the other side, the pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:

P×V = n×R×T

where:

P is the gas pressure.
V is the volume that occupies.
T is its temperature.
R is the ideal gas constant. The universal constant of ideal gases R has the same value for all gaseous substances.
n is the number of moles of the gas.

Then, in this case:

P= 1 atm
V= 44.1 L
n= ?
R= 0.082 $\frac{atmL}{molK}$
T= 0°C =273 K

Replacing in the expression for the ideal gas law:

1 atm× 44.1 L= n× 0.082 $\frac{atmL}{molK}$ × 273 K

Solving:

$n=\frac{1 atm x44.1 L}{0.082\frac{atmL}{molK}x273K}$

n=1.97 moles

Being the molar mass of O₂, that is, the mass of one mole of the compound, 32 g/mole, the amount of mass that 1.97 moles contains can be calculated as:

$1.97 molesx\frac{32 g}{1 mole}$ = 63.04 g ≈ 63 g

Finally, the correct answer is option e. 63 grams of O₂ are present in 44.1 L of O2 at STP.

Learn more about the ideal gas law:

brainly.com/question/4147359?referrer=searchResults

7 0

3 years ago

Solve the equation for n 0.0092=0.608 x (n/84.01)+n/52.5

kotegsom [21]

Answer:

$n\approx 0.350$

Explanation:

1. Rewrite the equation in a more appropriate format for a better understanding:

$0.0092=0.608\times \dfrac{n}{84.01}+\dfrac{n}{52.5}$

2. Multiply the whole equation (both sides) by 84.01 × 52.5 to eliminate the denominators:

$0.0092\times 84.01\times 52.5=0.608\times 52.5n+84.01n$

3. Do the operations:

$40.57683=31.92n+84.01n$

4. Add like terms:

$40.57683=115.93n$

5. Divide both sides by 115.93:

$0.350011\approx n\\\\n\approx 0.350011\\\\n\approx 0.350$

3 0

4 years ago

What is the chemical nature of q-sepharose that allows it to be used as an ion exchanger?

Lilit [14]

The chemical nature of Q sepharose which allows it to be used as an ion exchanger include the following: It is an insoluble matrix which is in form of micro beads. The bead are porous, which provides a large surface area within and outside them. This properties make it possible for Q sepharose to finely separate different organic molecules.

5 0

4 years ago

Which one is convection??? A heater in a fish tank warming the water at the bottom of the tank, Batteries in a flashlight conver

Travka [436]

Warming up next to a fire

7 0

3 years ago

Read 2 more answers

According to KMT, at constant pressure and temperature, the frequency and force of molecule-wall collisions are constant. So inc

Norma-Jean [14]

Answer:

Boyle´s Law

Explanation:

If we increase the volume of a gas, its pressure will decrease that is why in this question the pressure was decreased to yield the decrease in the number of collisions.

This is Boyle´s law which states that the pressure of a gas is inversely proportional to the volume of its container.

It is expressed mathematically as P₁V₁ = P₂V₂

where the subscripts refer to intial and final conditions.

3 0

3 years ago