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3 years ago

The test scores of the students in four classes are summarized below. Answer the questions about them.

Mathematics

1 answer:

aalyn [17]3 years ago

6 0

Answer:

Suppose that the mean score is M, and the range of scores is R.

The range is the difference between the largest score and the smallest score.

So, if the largest score is L, and the smallest score is S, we have:

R = L - S

Now, if the value of R increases, means that the difference between L and S also increases.

So having a large range usually is also a sign of having large variability.

Then:

a: Based on the information above, which class's scores have the most variability?

The class's scores with the most variability will be the class's scores with the largest range, in this case, the largest range of scores is for Class D.

b: Based on the information above, which class's scores have the least variability?

Now we need to look at the class with the least range of scores, in this case, the smallest one is the one for Class A.

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If 4x^2 - 100 = 0 then the roots of the equation are

iVinArrow [24]

4x² - 100 = 0
 + 100 + 100
 4x² = 100
 4 4
 x² = 25
 x = +5
4(5)² - 100 = 0
4(25) - 100 = 0
100 - 100 = 0
 0 = 0

4(-5)² - 100 = 0
4(25) - 100 = 0
 100 - 100 = 0
 0 = 0

The roots of the equation is positive or negative 5.

8 0

3 years ago

Read 2 more answers

At Elisa's printing company, there are two kinds of printing presses: Model A, which can print 70 books/ day, and model B, which

Dmitrij [34]

Answer:

9 Model As.

Step-by-step explanation:

Let A represent Press A and let B represent Press B.

So, they own 14 total presses. This means that:

$A+B=14$

They can print 905 books per day, in other words, since A prints 70 per day and B prints 55 per day:

$70A+55B=905$

This is now a system of equations. Solve by substitution. From the first equation, subtract B from both sides:

$A=14-B$

Substitute this into the second equation: "

$70(14-B)+55B=905$

First, we can divide everything by 5 to simplify things:

$14(14-B)+11B=181$

Distribute the left:

$196-14B+11B=181$

Combine like terms:

$-3B+196=181$

Subtract 196 from both sides:

$-3B=-15$

Divide both sides by -3

$B=5$

So, the company has 5 Model B presses.

Which means that the company has 14-5 or 9 Model A presses.

And we're done!

3 0

3 years ago

Help me asap! I will give you marks

Law Incorporation [45]

Recall the binomial theorem.

$(a+b)^n = \displaystyle \sum_{k=0}^n \binom nk a^{n-k} b^k$

1. The binomial expansion of $\left(1+\frac x3\right)^7$ is

$\left(1 + \dfrac x3\right)^7 = \displaystyle\sum_{k=0}^7 \binom 7k 1^{7-k} \left(\frac x3\right)^k = \sum_{k=0}^7 \binom 7k \frac{x^k}{3^k}$

Observe that

$k = 1 \implies \dbinom 71 \left(\dfrac x3\right)^1 = \dfrac73 x$

$k = 2 \implies \dbinom 72 \left(\dfrac x3\right)^2 = \dfrac73 x^2$

When we multiply these by $8-9x$ ,

• $8$ and $\frac73 x^2$ combine to make $\frac{56}3 x^2$

• $-9x$ and $\frac73 x$ combine to make $-\frac{63}3 x^2 = -21x^2$

and the sum of these terms is

$\dfrac{56}3 x^2 - 21x^2 = \boxed{-\dfrac73 x^2}$

2. The binomial expansion is

$\left(2a - \dfrac b2\right)^8 = \displaystyle \sum_{k=0}^8 \binom 8k (2a)^{8-k} \left(-\frac b2\right)^k = \sum_{k=0}^8 \binom 8k 2^{8-2k} a^{8-k} b^k$